6. a) Why is isocyanic acid prepared ""in situ"" in the Dulcin experiment? [2 pts] b) Draw a plausible Lewis structure for isocy
anic acid showing all lone pairs. The connectivity for isocyanic acid is shown below[4 pts] H-N-C-0
1 answer:
Answer:
As it gets hydrolyzed easily.
Explanation:
The isocyanic acid may get polymerizes easily into cyanuric acid and a polymer cyamelide
Also, even at 0 °C temperature it may react with mositure and gets hydrolyzed into ammonia an carbon dioxide. Thus we generally prepare it in situ. Even after synthesis it is stroed at dry ice or liquid nitrogen at very low temperature.
The lewis structure is shown in the figure.
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The molarity of the NaOH solution is 0.03 M
We'll begin by calculating the mole of the KHP
- Mass = 0.212 g
- Molar mass = 204.22 g/mol
- Mole of KHP =?
Mole = mass /molar mass
Mole of KHP = 0.212 / 204.22
Mole of KHP = 0.001 mole
Next, we shall determine the molarity of the KHP solution
- Mole of KHP = 0.001 mole
- Volume = 50 mL = 50/1000 = 0.05 L
- Molarity of KHP =?
Molarity = mole / Volume
Molarity of KHP = 0.001 / 0.05
Molarity of KHP = 0.02 M
Finally , we shall determine the molarity of the NaOH solution
KHP + NaOH —> NaPK + H₂O
From the balanced equation above,
- The mole ratio of the acid, KHP (nA) = 1
- The mole ratio of base, NaOH (nB) = 1
From the question given above, the following data were obtained:
- Volume of acid, KHP (Va) = 50 mL
- Molarity of acid, KHP (Ma) = 0.02 M.
- Volume of base, NaOH (Vb) = 35 mL
- Molarity of base, NaOH (Mb) =?
MaVa / MbVb = nA / nB
(0.02 × 50) / (Mb × 35) = 1
1 / (Mb × 35) = 1
Cross multiply
Mb × 35 = 1
Divide both side by 35
Mb = 1 / 35
Mb = 0.03 M
Thus, the molarity of the NaOH solution is 0.03 M
Complete question:
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Learn more about titration: brainly.com/question/25866669
Answer:
the answer is 25.032g check pic for explanation
