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Aleks04 [339]
2 years ago
13

Gaseous methane CH4 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the t

heoretical yield of water formed from the reaction of 15.4g of methane and 90.3g of oxygen gas
Chemistry
1 answer:
Murrr4er [49]2 years ago
8 0

Answer:

50.8 g

Explanation:

Equation of reaction.

CH_4 + 2O_2 \to CO_2 + 2H_2O

From the given information, the number of moles of methane = mass/ molar mass

= 15.4 g /  16.04 g/mol

= 0.960 mol

number of moles of oxygen gas = 90.3 g / 32 g/ mol

= 2.82 mol

Since 1 mol of methane requires 2 moles of oxygen

Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas

Thus, methane serves as a limiting reagent.

2.82 mol oxygen gas will result in 2.82 moles of water

So, the theoretical yield of water = moles × molar mass

= 2.82 mol × 18.01528 g/mol

= 50.8 g

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