Answer:
When [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate
Explanation:
Ksp of BaF₂ is:
BaF₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)
Ksp = 1.7x10⁻⁶ = [Ba²⁺] [F⁻]²
The solution will produce BaF₂(s) -precipitate- just when [Ba²⁺] [F⁻]² > 1.7x10⁻⁶.
As the concentration of [Ba²⁺] is 0.0144M, the product [Ba²⁺] [F⁻]² will be equal to ksp just when:
1.7x10⁻⁶ = [Ba²⁺] [F⁻]²
1.7x10⁻⁶ = [0.0144M] [F⁻]²
1.18x10⁻⁴ = [F⁻]²
0.0109M = [F⁻]
That means, when [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate
<h3>SUBSTANCE</h3>
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- Substances that cause the oxidation of other substances are;
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- Substances that cause the oxidation of other substances are oxidizing agents.
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Answer:
The density of water
.
Explanation:
Density of water = 1.00 g/mL
1 lb = 453.592 g



Density of the water in
:


The density of water
.
<u>Answer:</u>
<em>Theoretical density values </em>
- brass-

- bronze-

- steel-

<u>Explanation:</u>
All of these substances are<em> </em>alloys (a substance made from melting two or more substances, one of them usually being a metal). Brass is a combination of copper and zinc, bronze is mostly copper, tin and other non-metals as well and steel is majorly made up of iron and copper. These alloys have various uses and varying importance in different kinds of industries.
I think that pressure will affect the solubility of gasses the most. The reason why I think this is that gasses are affected the most by pressure change. By definition solids and liquids are not easily affected by pressure by how close the molecules are to each other in both of those phases.
I hope this helps. Please let me know if you have any further questions or need any clarification.