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3 years ago

PLEASE HELP FAST!!!! Which of the following is NOT an intensive physical property?

Chemistry

2 answers:

Zarrin [17]3 years ago

7 0

Volume is an extensive physical property and not an intensive one.

Allushta [10]3 years ago

5 0

Answer:

Volume

Step-by-step explanation:

The volume of a substance depends on how much you have. Thus, volume is not an intensive property. It is an extensive property.

Magnetism, boiling point, and thermal conductivity are <em>intensive properties</em>.They are the same, no matter how much of the substance you have.

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When a substance such as salt is dissolved in water, it is said to enter into the _____ state.

Lunna [17]

Water can dissolve salt because the positive part of water molecules attracts the negative chloride ions and the negative part of water molecules attracts the positive sodium ions. The amount of a substance that can dissolve in a liquid (at a particular temperature) is called the solubility of the substance.

6 0

3 years ago

Read 2 more answers

How many moles of Cl2 are needed in order to produce 100.0 grams of FeCl3 given the following

dimulka [17.4K]

Answer:

0.92moles

Explanation:

Given reaction:

2Fe + 3Cl₂ → 2FeCl₃

Mass of FeCl₃ = 100g

Unknown:

Number of moles of Cl₂ needed = ?

Solution:

To solve this problem, we work from the known specie to the unknown.

From the mass of the FeCl₃ given, we can solve for the number of moles of the unknown.

Number of moles of FeCl₃;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of FeCl₃ = 56 + 3(35.5) = 162.5g/mol

Number of moles = $\frac{100}{162.5}$ = 0.62mole

From the reaction expression;

2 mole of FeCl₃ is produced from 3 moles of Cl₂

0.62 mole of FeCl₃ will be produced from $\frac{0.62 x 3}{2}$ = 0.92mole

The number of moles of Cl₂ = 0.92moles

5 0

3 years ago

Nickel metal will react with CO gas to form a compound called nickel tetracarbonyl (Ni(CO)4), which is a gas at temperatures abo

Bad White [126]

Answer:

The final total pressure in the bulb will be 0.567 atm.

Explanation:

The equation of the reaction is:

Ni + 4CO → Ni(CO)₄

The pressure in the bulb will be the sum of the pressures of each gas (remaining CO and Ni(CO)₄ produced).

The pressure of each gas can be calculated using this equation:

For the gas Ni(CO)₄:

P(Ni(CO)₄) = n * R * T / V

where:

P(Ni(CO)₄) = pressure of Ni(CO)₄

n = number of moles of Ni(CO)₄.

R = gas constant = 0.082 l amt / K mol

T = temperature

V = volume

So we have to find how many moles of Ni(CO)₄ were produced and how many moles of CO remained unreacted.

We can calculate the initial number of moles of CO with the data provided in the problem:

P(CO) = n * R * T / V

solving for n:

P(CO) * V / R * T = n

Replacing with the data:

1.20 atm * 1.50 l / 0.082 (l atm / K mol) * 346K = n

n = 0.06mol.

Now we know how many moles of CO were initially present.

To know how many moles of Ni(CO)₄ were produced, we have to find how many Ni reacted with CO.

Initially, we have 0.5869 g of Ni, which is (0.5869 g * 1 mol/58.69 g) 0.01 mol Ni.

From the chemical equation, we know that 1 mol Ni reacts with 4 mol CO, therefore, 0.01 mol Ni will react with 0.04 mol CO producing 0.01 mol Ni(CO)₄ (see the chemical equation above).

At the end of the reaction, we will have 0.01 mol Ni(CO)₄ and (0.06 mol - 0.04 mol) 0.02 mol CO.

Now we can calculate the pressure of each gas after the reaction:

PNi(CO)₄ = n * R * T / V

PNi(CO)₄ = 0.01 mol * 0.082 (l amt / K mol) * 346K / 1.50 l = 0.189 atm

In the same way for CO:

P(CO) = 0.02 mol * 0.082 (l amt / K mol) * 346K / 1.50 l = 0.189 atm = 0.378 atm

The total pressure (Pt) in the bulb, according to Dalton´s law of partial pressures, is the sum of the pressures of each gas in the mixture:

Pt = PNi(CO)₄ + P(CO) = 0.189 atm + 0.378 atm = <u>0.567 atm.</u>

6 0

4 years ago

Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4.

noname [10]

Answer:

$Y_A=92.1\%\\\\Y_B=89.6\%$

Explanation:

Hello there!

In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:

$m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2} *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4$

Now, we are able to compute the percent yields, by using the actual yield each scientist got:

$Y_A=\frac{83.67g}{90.9g} *100\%=92.1\%\\\\Y_B=\frac{81.35g}{90.9g} *100\%=89.6\%$

Regards!

8 0

3 years ago

Student A pushed on the cart with a force of 500 N. Student B pushed on the other side of the cart. The cart did not move. How m

Nadusha1986 [10]

I depends on the height of the other side of the cart. If it was lower, 400 N. If Higher, at least 600 N.

5 0

4 years ago