I shoot a bullet up at 270 m/s. How long does it fly for????

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leav

nata0808 [166]

Answer:

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball, $v=65\ cos(30)=56.29\ m/s$

Time of contact, $t=1.75\ ms=1.75\times 10^{-3}\ s$

(a) It is assumed to find the horizontal component of average force. It is given by :

$F=m\dfrac{v-u}{t}$

$F=0.145\dfrac{56.29-60}{1.75\times 10^{-3}}$

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

8 0

3 years ago

The unit of measure for resistance is volt coulomb ohm watt ampere

Alika [10]

The ohm is the unit measure of resistance.

4 0

3 years ago

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A vector in the xy plane has components -14.0 units in the x-direction and 30.0 units in the y-direction. What is the magnitude

OverLord2011 [107]

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

We would calculate the magnitude by applying pythagorean theorem:

$\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}$

$\longrightarrow \sf{Magnitude = 33.12}$

$\longrightarrow \sf{The \: vector \: is \: (- 14, 30)}$

The angle between two vectors is given by the formula:

$\sf{\longrightarrow \small \cos \emptyset = \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }$

In two dimensional, the x axis of vector form is:

$\small\sf{\longrightarrow (b1, b2) = (1, 0) }$

$\sf{\longrightarrow \small \cos \: \emptyset = \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }$

$\small\longrightarrow \sf{ \dfrac{14}{33.12} }$

$\small\longrightarrow \sf{\emptyset \: = arcCos (\dfrac{ - 14}{33.12} )}$

$\small\longrightarrow \sf{\emptyset= 115^\circ}$

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\small\bm{The \: angle \: between \: the \: vector \: }$

$\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}$

6 0

2 years ago

HELP!!!!!!!!!!!!!!!!!!

Andrews [41]

Answer:

d.

Explanation:

4 0

3 years ago

A 19.0-kg cart is moving with a velocity of 7.20 m/s down a level hallway. A constant force of -13.0 N acts on the cart and its

gulaghasi [49]

Answer:

a. -369.36J

b. -123.9J

c. 9.52m

Explanation:

From the expression for kinetic energy

K. E=1/2mv^2

Since the mass is constant, but the velocity changes. Hence the change in kinetic energy is

K.E=1/2*19(3.6²-7.2²)

K.E= -369.36J

b. to determine the workdone by the force,we determine the distance moved.

But the acceleration is from

F=ma ,

a=f/m

a=-13/19

0.68m/s²

the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

Hence the work done is

W=force * distance

W=-13*9.52

W=-123.9J

d. the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

4 0

4 years ago

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