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jekas [21]
3 years ago
9

I shoot a bullet up at 270 m/s. How long does it fly for????

Physics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

5 minutes

Explanation:

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What is the difference between atomic structure and crystal structure?
mars1129 [50]
Atomic structure applies to just that, atoms in isolation. Witness looking at atomic spectra using laboratory discharge tubes to ionise low pressure gases of atoms of the elements you want to examine for energy level structure (sodium and the yellow D line "doublet").Crystal structure applies to vast collections of atoms/molecules/ions in complicated geometrical arrays which form lattices. Simple cubic, body centred cubic, face centred cubic being a few "simple" examples.
4 0
3 years ago
Please help!!! zoom in to read it clearly
Artist 52 [7]

Answer:

imma try nd help cuz i havent seen anybody answer so

1.sara

2.same for both

3.tom

Explanation:

4 0
3 years ago
Find the radius of the path described by a proton moving at 15 km/s in a plane perpendicular to a 400-g magnetic field.
Jet001 [13]

Answer:

The radius described the proton moving is

r=3.91mm

Explanation:

The magnetic field that moving the proton with the velocity

v=15 km/s

To find the radius combinate the magnetic field with the mass of the proton and the charge of the proton

r = mv=eB

r = mv/eB

r=\frac{(1.67*10^{-27})*(15\frac{km}{s})}{(1.6*10^{-19})(4*10^-2kg)}

r = 3.9mm

6 0
3 years ago
In physics, Ohm's law says that current through a wire, I, is directly proportional to voltage, V, and inversely proportional to
jeka94

Due to Ohm's law, I is proportional to V and 1/R:

I ∝ V

I ∝ 1/R

R is proportional to the wire length L:

R ∝ L

Therefore I is also proportional to 1/L:

I ∝ 1/L

Calculate the scale factor due to increased voltage:

k₁ = 24/12 = 2

Calculate the scale factor due to decreased wire length:

k₂ = 1/(0.5/1) = 2

Multiply the original current by the scale factors to get the new current:

I = I₀k₁k₂

I₀ = 100mA, k₁ = 2, k₂ = 2

I = 100(2)(2)

I = 400mA

3 0
3 years ago
A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition
Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So mg=Kx

K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m

Now we know that \omega =\sqrt{\frac{K}{m}}

So \frac{2\pi }{T} =\sqrt{\frac{K}{m}}

\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}

T=2.1371sec

8 0
3 years ago
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