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Yuki888 [10]
3 years ago
13

If a ball is dropped from rest, what is it’s velocity after 4 seconds

Physics
1 answer:
Ghella [55]3 years ago
4 0

Answer: -39.2 m/s directed downwards

Explanation:

We can solve this problem with the following equation:

V=V_{o}+gt

Where:

V is the ball's velocity at 4 s

V_{o}=0m/s is the ball's intial velocity, since it was dropped from rest

g=-9.8 m/s^{2} is the acceleration due gravity, aways directed downwards

t=4 s is the time

Solving:

V=0m/s-9.8 m/s^{2}(4 s)

Finally:

V=-39.2 m/s <u>The negative sign indicates the velocity is downwards</u>

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Is an imaginary "line" from the earth to the moon a line, a ray, or a segment? Why?
igomit [66]

Answer;

- Line segment

Explanation;

"from earth to moon" implies endpoints at both locations and it is thus a line segment

A line extends forever in both directions, a line segment is just part of a line. It has two endpoints, and a ray starts at one point and continues on forever in one direction.

5 0
3 years ago
A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t
enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

v_{avg} = \frac{6000}{20*60}

v_{avg} = 5m/s

now since effect of wind is in opposite direction then we can say

V_{net} = v_{bird} - v_{wind}

5 = 9 - v_{wind}

v_{wind}= 4 m/s

Part b)

now if bird travels in the same direction of wind then we will have

v_{net}= v_{bird} + v_{wind}

v_{net} = 9 + 4 = 13 m/s

now we can find the time to go back

time = \frac{distance}{speed}

time = \frac{6000}{13}

time = 7.7 minutes

Part c)

Total time of round trip when wind is present

T = t_1 + t_2

T = 20 + 7.7 = 27.7 min

now when there is no wind total time is given by

T = \frac{6000}{9} + \frac{6000}{9}

T = 22.22 min

So due to wind time will be more

4 0
3 years ago
A 0.325 g wire is stretched between two points 57.7 cm apart. The tension in the wire is 650 N. Find the frequency of first harm
Galina-37 [17]

Answer:

f = 931.1 Hz

Explanation:

Given,

Mass of the wire, m = 0.325 g

Length of the stretch, L = 57.7 cm = 0.577 m

Tension in the wire, T = 650 N

Frequency for the first harmonic = ?

we know,

v =\sqrt{\dfrac{T}{\mu}}

μ is the mass per unit length

μ = 0.325 x 10⁻³/ 0.577

μ = 0.563 x 10⁻³ Kg/m

now,

v =\sqrt{\dfrac{650}{0.563\times 10^{-3}}}

   v = 1074.49 m/s

The wire is fixed at both ends. Nodes occur at fixed ends.

For First harmonic when there is a node at each end and the longest possible wavelength will have condition

          λ=2 L

          λ=2 x 0.577 = 1.154 m

we now,

       v = f λ

      f = \dfrac{v}{\lambda}

      f = \dfrac{1074.49}{1.154}

             f = 931.1 Hz

The frequency for first harmonic is equal to f = 931.1 Hz

7 0
3 years ago
Why is specific heat important
Ad libitum [116K]
Hey!!

here is your answer >>>

Specific heat is the amount of heat required to raise the temperature of a unit substance!. The most common example!. The specific heat of water is 1 !. And, lot of plays and animals live under the water and if the specific heat of the water would be low, then the aquatic organisms would die, but the specific heat is high and it is hard for the sun to increase the temperature!.

Hope my answer helps!
3 0
3 years ago
An object at rest will ______ unless acted upon by an unbalanced force.
zvonat [6]

Answer:

It's C because if you were trying to put it at rest that means you would put it on a Balanced surfest

4 0
2 years ago
Read 2 more answers
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