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Yuki888 [10]
3 years ago
13

If a ball is dropped from rest, what is it’s velocity after 4 seconds

Physics
1 answer:
Ghella [55]3 years ago
4 0

Answer: -39.2 m/s directed downwards

Explanation:

We can solve this problem with the following equation:

V=V_{o}+gt

Where:

V is the ball's velocity at 4 s

V_{o}=0m/s is the ball's intial velocity, since it was dropped from rest

g=-9.8 m/s^{2} is the acceleration due gravity, aways directed downwards

t=4 s is the time

Solving:

V=0m/s-9.8 m/s^{2}(4 s)

Finally:

V=-39.2 m/s <u>The negative sign indicates the velocity is downwards</u>

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In an inelastic collision a 2.5 kg ball moving at 7.5 m/s is caught by a 70kg man while the man is standing on ice. What is the
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The velocity of the ball and the man is 0.259 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in an isolated system, the total momentum before and after the collision must be conserved. Therefore, for the ball-man system, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v

where:

m_1 = 2.5 kg is the mass of the ball

u_1 = 7.5 m/s is the initial velocity of the ball

m_2 = 70 kg is the mass of the man

u_2 = 0 is the initial velocity of the man

v is the final velocity of the man and the ball after the collision

Re-arranging the equation and substituting the values, we find the final velocity:

v=\frac{m_1 u_1}{m_1+m_2}=\frac{(2.5)(7.5)}{2.5+70}=0.259 m/s

So, the man and the ball slides on the ice at 0.259 m/s.

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A parcel has a mass of 500 g .calculate its weight (assume the gravitational field strength is 10 N/Kg
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Answer:

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Explanation

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The tow spring on a car has a spring constant of 3,086 N / m and is initially stretched 18.00 cm by a 100.0 kg college student o
sdas [7]

Answer:

The velocity of the skateboard is 0.774 m/s.

Explanation:

Given that,

The spring constant of the spring, k = 3086 N/m

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Potential energy of the spring, P_f=20\ J

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P_i=K_f+P_f

\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2+20

\dfrac{1}{2}\times 3086\times (0.18)^2=\dfrac{1}{2}mv^2+20

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