Actually Welcome to the concept of Efficiency.
Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%
The efficiency is => 22% => 22/100.
so we get as,
E = W(output) /W(input)
hence, W(output) = E x W(input)
so we get as,
W(output) = (22/100) x 2.2 x 10^7
=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7
hence, W(output) = 4.84 x 10^6 J
The useful work done on the mass is 4.84 x 10^6 J
Answer:
Explanation:
In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).
From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:
so:
now we can go ahead and do a sum of forces in the x-direction:
the sum of forces in x is 0 because it's moving at a constant speed.
so now we solve for theta. We can start by factoring mg so we get:
we can divide both sides into mg so we get:
this tells us that the problem is independent of the mass of the object.
we now divide both sides of the equation into so we get:
so we now take the inverse function of tan to get:
so now we can find our angle:
so
