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Gennadij [26K]
3 years ago
9

1 Point

Physics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

SECOND LAW OF NEWTON

Explanation:

When the rocket fires the engines the gases leave at high speed and collide with the space station, transferring an impulse given by the expression

                I = F t = Δp

As we can see this expression is a form of Newton's second law

           F = m a

           a = dv / dt

           F = m dv / dt

           F dt = m dv

           p = mv

           F dt = dp

Therefore the station moves through the SECOND LAW OF NEWTON

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What will happen to the current if the voltage is reduced to one half? ​
stira [4]
We use v=IR and assuming the resistance doesn’t change we can also say that the voltage and current (I) are directly proportional which means the voltage also decreases by 1/2
8 0
2 years ago
1. 1500j of work was done to move a box 20m. What force was applied to the box ?
Fantom [35]

Answer:

1. 75N

2. 67,983 J (=67.98 kJ)

Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

Work = Force x Distance

1,500 = Force x 20

Force = 1,500 ÷ 20 = 75N

2. Potential Energy, PE = mass x gravity x change in height

we are given that mass = 165 kg and change in height = 42m

assuming that gravity, g = 9.81 m/s²

Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

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3 years ago
An infrared wave traveling through a vacuum has a frequency of 4.2
ololo11 [35]

Answer:O 7.1x10^-7 m

Explanation:

3 0
3 years ago
Read 2 more answers
A wheel initially has an angular velocity of 18 rad/s, but it is slowing at a constant rate of 2 rad/s 2 . By the time it stops,
ZanzabumX [31]

Answer:

5) 13 revolutions (approximately)

Explanation:

We apply the equations of circular motion uniformly accelerated :

ωf²= ω₀² + 2α*θ Formula (1)

Where:

θ : angle that the body has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed  ( rad/s)

Data:

ω₀ = 18 rad/s

ωf = 0

α = -2 rad/s²  ; (-) indicates that the wheel is slowing

Revolutions calculation that turns the wheel until it stops

We apply the formula (1)

ωf²= ω₀² + 2α*θ

0 = (18)² + 2( -2)*θ

4*θ =  (18)²

θ =  (18)²/4 = 81 rad

1 revolution = 2π rad

θ = 81 rad * 1 revolution / 2πrad

θ =  13 revolutions approximately

8 0
3 years ago
A 90kg cannon fires 100kg shell with muzzle velocity of 75m/s. Calculate the recoil velocity of the cannon relative to the groun
Gala2k [10]

Answer: 83.8 m/s

Explanation:

momentum of shell = momentum of cannon

M(s) × V(s) = M(c) × V(c)

M(s) = mass of shell, V(s) = velocity of shell

M(c) = mass of cannon, V(c) = velocity of cannon

100kg × 75m/s = 90kg × V(c)

7500 = 90 × V(c)

7500 ÷ 90 = V(c)

83.3 = V(c)

5 0
3 years ago
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