Answer:
1.72 x 10³ N.
Explanation:
When a charge is split equally and placed at a certain distance , maximum electrostatic force is possible.
So the charges will be each equal to
31/2 = 15.5 x 10⁻⁶ C
F = K Q q / r²
= 
= 1.72 x 10³ N.
<span>3.36x10^5 Pascals
The ideal gas law is
PV=nRT
where
P = Pressure
V = Volume
n = number of moles of gas particles
R = Ideal gas constant
T = Absolute temperature
Since n and R will remain constant, let's divide both sides of the equation by T, getting
PV=nRT
PV/T=nR
Since the initial value of PV/T will be equal to the final value of PV/T let's set them equal to each other with the equation
P1V1/T1 = P2V2/T2
where
P1, V1, T1 = Initial pressure, volume, temperature
P2, V2, T2 = Final pressure, volume, temperature
Now convert the temperatures to absolute temperature by adding 273.15 to both of them.
T1 = 27 + 273.15 = 300.15
T2 = 157 + 273.15 = 430.15
Substitute the known values into the equation
1.5E5*0.75/300.15 = P2*0.48/430.15
And solve for P2
1.5E5*0.75/300.15 = P2*0.48/430.15
430.15 * 1.5E5*0.75/300.15 = P2*0.48
64522500*0.75/300.15 = P2*0.48
48391875/300.15 = P2*0.48
161225.6372 = P2*0.48
161225.6372/0.48 = P2
335886.7441 = P2
Rounding to 3 significant figures gives 3.36x10^5 Pascals.
(technically, I should round to 2 significant figures for the result of 3.4x10^5 Pascals, but given the precision of the volumes, I suspect that the extra 0 in the initial pressure was accidentally omitted. It should have been 1.50e5 instead of 1.5e5).</span>
Answer:the answer should be dark energy
Explanation:
Answer:
2.83m
Explanation:
The information that we have is
Intensity at 2.0 m:
and 
we need an intensity level of: 
thus, we are looking for the distance
.
which we can find with the law for intensity and distance:

we solve for
:

and we substitute the known values:

at a distance of 2.83m the intensity level is 40dB
Answer:
s = 307.34 m
Explanation:
In order to find the distance covered by the dragster during the given time, we will use second equation of motion. The second equation of motion is written as follows:
s = Vi t + (0.5)at²
where,
s = distance covered by the dragster = ?
Vi = Initial Velocity = 0 m/s
t = time interval = 3.97 s
a = acceleration = 39 m/s²
Therefore,
s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²
<u>s = 307.34 m</u>