Use the periodic table entry below to answer the following question.

Chemistry

1 answer:

Komok [63]3 years ago

6 0

The answer is 59
the atomic mass is the number at the bottom so you've gotta round it to the nearest whole number

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Which statement is true about the concentration of the reactants and products in chemical equilibrium?

bulgar [2K]

Answer:

Ans: 2

Explanation:

The concentration of reactants and the concentration of products are constant.

5 0

3 years ago

A solution is made by dissolving 0.656 mol of nonelectrolyte solute in 869 g of benzene. calculate the freezing point, tf, and b

solmaris [256]

Answer is: the freezing point is 1.63°C and boiling point is 82.01°C..

1) n(nonelectrolyte solute) = 0.656 mol.
m(C₆H₆ - benzene) = 869 g ÷ 1000 g/kg.
m(C₆H₆) = 0.869 kg.
b(solution) = n(nonelectrolyte solute) ÷ m(C₆H₆).
b(solution) = 0.656 mol ÷ 0.869 kg.
b(solution) = 0.754 mol/kg.

2) ΔT = Kf(benzene) · b(solution).
ΔT = 5.12°C/m · 0.754 m.
ΔT = 3.865°C.
Tf = 5.50°C - 3.865°C.
Tf = 1.63°C.

3) ΔTb = Kb(benzene) · b(solution).
ΔTb = 2.53°C/m · 0.754 m.
ΔTb = 1.91°C.
Tb = 80.1°C + 1.91°C.
Tb = 82.01°C.

4 0

3 years ago

When 2-phenylacetaldehyde is added dropwise to benzaldehyde in the presence of sodium hydroxide they undergo a crossed aldol rea

egoroff_w [7]

Carbonyl Compounds containing alpha proton readily donates alpha acidic proton when treated with strong Base. In given statement 2-phenylacetaldehyde is converted into Enolate and Enolates acts as a nucleophile and attacks carbonyl group of Benzaldehyde. The mechanism of given reaction is as follow, the movement of electrons is shown by RED arrows,

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3 years ago

Convert 100mL to L. Show your work to receive full credit.

Ilya [14]

Answer:

100 ml = 0.1 L

I divided 100 by 1000 because 1000ml = 1L

3 0

3 years ago

Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo

Romashka-Z-Leto [24]

Answer:

$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

Explanation:

Volume of a cone:

$\displaystyle V=\frac{1}{3} \pi r^2 h$

We have $\displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec}$ and we want to find $\displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ?$ when the height is 2 cm.