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nadezda [96]
3 years ago
14

space capsules operate with an oxygen content of about 34%. assuming a total pressure of 780 mm Hg in the space capsule, what is

the partial pressure of the oxygen?
Chemistry
1 answer:
Lemur [1.5K]3 years ago
7 0

265.2 mmHg is the partial pressure of oxygen in 780 mmHg of total pressure.

Explanation:

The partial pressure of a gas is defined as the individual pressure of the gas in total mixture. In an ideal gas all the constituent gases have partial pressure some of which will give total pressure of the gas.

The partial pressure of a gas is calculated by

total pressure x mole fraction of the gas.

Mole fraction of the oxygen present is 0.34 as it is 34% of the total gas.

\frac{34}{100} = 0.34  is the mole fraction

Total pressure is given as 780 mm Hg

The partial pressure can be calculated using the above formula:

Putting the values in equation:

780 x 0.34

= 265.2 mm Hg is the partial pressure of oxygen.

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The question is incomplete, here is the complete question:

The solubility of substance X in water at a certain temperature is 35.7 g /100. g. Suppose that you have 330.0 g of substance X. What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)

<u>Answer:</u> The minimum volume of water that would be needed is 940.17 mL

<u>Explanation:</u>

We are given:

Solubility of substance X in water = 35.1 g/100 g

This means that 35.1 grams of substance X is dissolved in 100 grams of water

Applying unitary method:

If 35.1 grams of substance X is dissolved in 100 grams of water

So, 330.0 grams of substance X will be dissolved in = \frac{100}{35.1}\times 330=940.17g of water

To calculate the volume of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

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Mass of water = 940.17 g

Putting values in above equation, we get:

1g/mL=\frac{940.17g}{\text{Volume of water}}\\\\\text{Volume of water}=\frac{940.17g}{1g/mL}=940.17mL

Hence, the minimum volume of water that would be needed is 940.17 mL

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