When you find something that interests you, how do you make a hypothesis

2 answers:

4 0

A hypothesis is an educated guess, so what I think would be a good way to make a hypothesis is to research the topic a little bit, and make an assumption based on what you learned.

Like, say I'm interested in gases in balloons. I researched, and now I know that helium-filled balloons rise to the ceiling and balloons filled with regular air don't. I'm going to say, based on that, that helium is less dense than air which causes it to rise to the ceiling. I may or may not be right, but it doesn't matter right now. All that matters is that I can come up with an experiment to test my hypothesis! So my experiment would be testing if helium is actually less dense than air.

Misha Larkins [42]2 years ago

4 0

What Makes a Good Hypothesis? For a Good Hypothesis, You Should Answer "Yes" to Every Question
Is the hypothesis based on information from reference materials about the topic? Yes / No
Can at least one clear prediction be made from the hypothesis? Yes / No
Are predictions resulting from the hypothesis testable in an experiment? Yes / No
Does the prediction have both an independent variable (something you change) and a dependent variable (something you observe or measure)?

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A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work

DENIUS [597]

Data:
$V_{initial} = 590\:mL$
$T_{initial} = -55.0^0C$
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → $T_{initial} = 218.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 30.0^0C$
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → $T_{final} = 303.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }$
Product of extremes equals product of means:
$218.0* V_{f} = 590*303.0$
$218.0 V_{f} = 178770$
$V_{f} = \frac{178770}{218.0}$
$\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark$

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Im a bit torn here, lets look at the definitions of physical and chemical changes:
physical change changes only the phase/state of a substance, but not what the substance is
chemical change is a chemical reaction where a new substance is formed and energy is given off or absorbed.
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clearly, this cannot be just a physical reaction. i think i would be inclined to pick B. but C. could have merit as an answer too. sorry for the ambiguity x

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