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3 years ago

A 45-gram object that has a volume of 9 mL has a density of

Physics

1 answer:

yanalaym [24]3 years ago

7 0

Answer:

<h2> The answer is </h2><h2>a. 5g/mL</h2>

Explanation:

Given data

mass m= 45g

volume v= 9mL

we know that density=m/v

substituting our given data we have

$density=\frac{45}{9} =5g/mL$

What is Density?

The Density of a body can be defined as the ratio of mass to volume,

Density, mass of a unit volume of a material substance. The formula for density is $Density= \frac{mass}{volume}$ ,

where d is density,

M is mass, and

V is volume.

Density is commonly expressed in units of grams per cubic centimetre.

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Compare the collision between two baseballs and a catcher's mitt.

Nookie1986 [14]

The applied force is different for the two cases

The case A with a greater force involves the greatest momentum change

The case A involves the greatest force.

<h3>What is collision?</h3>

This is the head-on impact between two object moving in opposite or same direction.

The initial momentum of the two ball is the same.

P = mv

where;

m is the mass of each
v is the initial velocity of each ball

Since the force applied by the arm is different, the final velocity of the balls before stopping will be different.

Thus, the final momentum of each ball will be different

The impulse experienced by each ball is different since impulse is the change in momentum of the balls.

J = ΔP

The force applied by the rigid arm is greater than the force applied by the relaxed arm because the force applied by the rigid arm will cause the ball to be brought to rest faster.

Thus, we can conclude the following;

The applied force is different for the two cases
The case A with a greater force involves the greatest momentum change
The case A involves the greatest force.

Learn more about impulse here: brainly.com/question/25700778

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3 years ago

An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti

shusha [124]

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

$I=F\Delta t$

where:

I is the impulse

F is the force exerted on the object

$\Delta t$ is the time during which the force is applied

For the object in this problem, we have

$F=106 N$ (force applied)

$\Delta t= 15.6 s$ (time interval)

Therefore, the impulse experienced by the object is:

$I=(106)(15.6)=1654 kg m/s$

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3 years ago