The speed of light to be slightly less in atmosphere then in vacuum because of absorption and re-emission of light by the atmospheric molecules occurred when light travels through a material
<u>Explanation:</u>
When light passes through atmosphere, it interacts or transmits through the transparent molecules in atmosphere. In this process of transmission through atmosphere, the light will be getting absorbed by them and some will get re-emitted or refracted depending upon wavelength.
But in vacuum the absence of any kind of particles will lead to no interaction and no energy loss, thus the speed of the light will be same in vacuum while due to interactions with molecules of atmosphere, there speed will be slightly less compared to in vacuum.
Density offers a convenient means of obtaining the mass of a body from its volume or vice versa; the mass is equal to the volume multiplied by the density (M = Vd), while the volume is equal to the mass divided by the density (V = M/d).
M = V d
M = 1.4 * 2 = 2.8 kg
Answer:
<em>The Antarctic blue whale </em>
Explanation:
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No, because superconductivity cannot occur if there is resistance
In addition to explaining electrical resistance, equilibrium distance theory also foretells the existence of superconductivity. According to its postulates, electrical resistivity decreases with distance from the equilibrium. There is only superconductivity at zero distance, with no resistance
<h3>What is Superconductivity ?</h3>
The ability of some materials to transmit electric current with virtually little resistance is known as superconductivity.
- This ability has intriguing and maybe beneficial ramifications. Low temperatures are necessary for a material to exhibit superconductor behaviour. H. K. made the initial discovery of superconductivity in 1911.
- Aluminum, magnesium diboride, niobium, copper oxide, yttrium barium, and iron pnictides are a few well-known examples of superconductors.
Learn more about Superconductivity here:
brainly.com/question/17166152
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Hello,
<span>A car with a mass of 2.0×10^3 kg is traveling at 15m/s. We need to find the momentum of the car. To do so, follow this formula:
p=mv
Where,
p = momentum
m = mass
v = </span>velocity
The cars mass is 2.0E3 and its velocity is 15m/s. Therefore:
p=2.0 x 10^3 *15 or 2000(15)
p=30000
Thus, the cars momentum is 30000 kg m/s
Faith xoxo