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Answer:
a) W = 5360 J b) μ = 0.29
Explanation:
a) The work is, bold indicate vectors
W = F. d = F d cos T
W = 40 268 cos 60
W = 5360 J
b) The force of friction and opposes the movement of the body and if the speed of the body is constant implies that the external force in the direction of the movement is equal to the force of friction, or which work is the same
= -5360J
The negative sign is because the force of friction is contrary to the direction of movement
c) Let's write the work of the friction force
= fr d cos 180
fr = μ N
Since the body is on a horizontal surface, from Newton's second law on the Y axis
N-W = 0
N = W
fr = μ W
= - μ W d
μ = - / W d
μ = - (-5360) / 69 268
μ = 0.29
6.07 moles
Explanation:
Given parameters:
Number of moles of reacting hydrogen gas = 9.1 moles
Unknown:
Number of moles of ammonia produced = ?
Solution:
Balanced chemical equation:
N₂ + 3H₂ → 2NH₃
We should work from the known to the unknown specie. We known the number of moles of hydrogen gas reacting. We simply relate this to that of the ammonia.
From the reaction:
3 mole of hydrogen gas produced 2 mole of ammonia
9.1 moles of the hydrogen gas will produce:
= 6.07 moles
Learn more:
Number of moles brainly.com/question/1841136
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