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Leviafan [203]
3 years ago
11

What does the term electron orbital describe? What does the term electron orbital describe? An electron orbital describes a thre

e-dimensional space where an electron can be found 90% of the time. An electron orbital describes the exact distance of an electron from the nucleus. An electron orbital describes the orbit of an electron around the nucleus.
Physics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

An electron orbital describes a three-dimensional space where an electron can be found 90% of the time.

Explanation:

According to Heisenberg's theory we cannot observe the position and velocity of an electron in an orbit, but if they were around the nucleus (in orbit), it would be possible to know its velocity and position, which would be contrary to the principle of Heisenberg So we can say that no electron revolves around a certain orbit around the nucleus, so we can only predict if the electron will be in the right position at the right time.

From there we find two definitions for electron orbital let's see:

  • Orbital is considered the region of space, where each electron spends most of its time.
  • Orbital is considered the region of space that is most likely to find an electron.
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Answer:

Amihan is known as the Northeast monsoon while Habagat is known as the Southwest monsoon.

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He conducted experiments in combining elements
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The block in the drawing has dimensions L0×2L0×3L0,where L0 =0.5 m. The block has a thermal conductivity of 200 J/(s·m·C˚). In d
Dennis_Churaev [7]

Answer:

Q_p=18000\ J

Q_o=8000\ J

Q_g=72000\ J

Explanation:

Given:

  • Length of block, l=3L_o=3\times 0.5=1.5\ m
  • Breadth of block, b=L_o=0.5\ m
  • height of block, h=2L_o=2\times 0.5=1\ m
  • Thermal conductivity of the block, k=200\ W.m.^{\circ}C
  • Temperature on the hotter side, T_H=37^{\circ}C
  • temperature on the cooler side, T_L=7^{\circ}C
  • time for which the heat flows, t=4\ s

<u>REFER THE ATTACHED IMAGE FOR THE REFERENCE</u>

<em>The rate of heat flow using </em><em>Fourier's law</em><em> of conduction is given as:</em>

\frac{Q}{t}=k.A.\frac{dT}{dx}

<u>Now the amount heat flow perpendicular to the pink surface:</u>

\frac{Q_p}{4}=200\times (0.5\times 1.5).\frac{30}{1}

Q_p=18000\ J

<u>Now the amount heat flow perpendicular to the orange surface:</u>

\frac{Q_o}{4}=200\times (0.5\times 1).\frac{30}{1.5}

Q_o=8000\ J

<u>Now the amount heat flow perpendicular to the green surface:</u>

\frac{Q_g}{4}=200\times (1.5\times 1).\frac{30}{0.5}

Q_g=72000\ J

6 0
4 years ago
The light we see coming from the moon is
kirill115 [55]
The answer would be reflected.
4 0
4 years ago
A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane
Mama L [17]

Answer:

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, \phi=8.6\times 10^{-3}\ T/m^2

The magnetic flux linked through the loop is :

\phi=B.A

\phi=BA\ cos\theta

Here, \theta=0

B=\dfrac{\phi}{A}

or

B=\dfrac{\phi}{\pi r^2}

B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

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3 years ago
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