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Leviafan [203]
3 years ago
11

What does the term electron orbital describe? What does the term electron orbital describe? An electron orbital describes a thre

e-dimensional space where an electron can be found 90% of the time. An electron orbital describes the exact distance of an electron from the nucleus. An electron orbital describes the orbit of an electron around the nucleus.
Physics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

An electron orbital describes a three-dimensional space where an electron can be found 90% of the time.

Explanation:

According to Heisenberg's theory we cannot observe the position and velocity of an electron in an orbit, but if they were around the nucleus (in orbit), it would be possible to know its velocity and position, which would be contrary to the principle of Heisenberg So we can say that no electron revolves around a certain orbit around the nucleus, so we can only predict if the electron will be in the right position at the right time.

From there we find two definitions for electron orbital let's see:

  • Orbital is considered the region of space, where each electron spends most of its time.
  • Orbital is considered the region of space that is most likely to find an electron.
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The eccentricity of its orbit is $$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

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The length of the semi-major axis is calculated as follows:

where, $G=6.67 \times 10^{-1} \mathrm{~m}^3 / \mathrm{kgs}$

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$$\begin{aligned}\therefore \quad \text { At aphelion, } r &=50 \times U \\&=50 \times 1.496 \times 10^{11} \mathrm{~m} . \\U=-\frac{6.67 \times 10^{-11} \times \mathrm{m} 1.99 \times 10^{30} \times 1.20 \times 10^{10}}{50 \times 1.496 \times 10^{11}} \\U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

$$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

To learn more about mass, refer to:

brainly.com/question/3187640

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2 years ago
An electron and a proton are each placed at rest in an electric field of 500 N/C. Calculate the speed (and indicate the directio
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Answer:

For proton: 2592 m/s In the same direction of electric field.

For electron: 4752000 m/s In the opposite direction of electric field.

Explanation:

E = 500 N/C, t = 54 ns = 54 x 10^-9 s,

Acceleration = Force /mass

Acceleration of proton, ap = q E / mp

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Acceleration of electron, ae = q E / me

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u = 0, ae = 8.8 x 10^13 m/s^2, t = 54 x 10^-9 s

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