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max2010maxim [7]
4 years ago
14

What is the distance between two points (3,4,-5) and (2,1,0,)

Physics
1 answer:
Dima020 [189]4 years ago
6 0

Answer:

\sqrt{35} \approx 5.91608

Explanation:

You use the 3D equivalent of Pythagoras:

\sqrt{(3-2)^2 + (4-1)^2 + (-5-0)^2} = \sqrt{1+9+25} = \sqrt{35} \approx 5.91608

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Which set of properties best describes a solid?
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3 years ago
When tightening a bolt, you push perpendicularly on a wrench with a force of 167 N at a distance of 0.1450 mm from the centre of
Vlad1618 [11]

Answer:0.0242 Nm

Explanation: The distance of 0.145 mm is very small. This will also result in a small ttorque. The question would make more sense if the distance was 0.145 m. Answering with the 0.145 mm as distance :

Changin from mm to m : 1mm=0.001m

0.145 mm = 0.000145 m

The formula for Torque is T=Fxd

Wher F is the force and d is the perpendicular distance between the centre of the bolt and the applied force.

T= 167 x 0.000145 = 0.024215 Nm

5 0
3 years ago
C.) 65 km =<br> mm<br> Convert
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6 0
3 years ago
Two ideal gases have the same mass density and the same absolute pressure. One of the gases is helium (He), and its temperature
Oxana [17]

Answer:

Temperature of neon gas = 875 K

Explanation:

Using Ideal gas equation as:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the temperature

Also,

moles=\frac{Mass(m)}{Molar\ mass (M)}

Density (\rho)=\frac{Mass(m)}{Volume(V)}

The ideal gas equation can be written as:

P=\frac{Mass(m)}{Molar\ mass (M)\times Volume(V)}\times RT

Thus,

P=\frac{Density (\rho)}{Molar\ mass (M)}\times RT

P\times M=Density (\rho)\times RT

As Density and Pressure is constant , We only consider molar mass and Temperature which are directly proportional according to the equation above as:

\frac {M_1}{T_1}=\frac {M_2}{T_2}

Data given for He:

Temperature (T₁) = 175 K

Molar mass of He (M₁)= 4 g/mol

For Ne:

Temperature (T₂)= ?

Molar mass of He (M₂)= 20 g/mol

Applying in the equation,

T_2=\frac {M_2}{T_1} \times {M_1}

T_2=\frac {20 g{mol}^{-1}}{175 K} \times {4 g{mol}^{-1}}

T_2=875 K atm

<u>Temperature of neon gas = 875 K</u>

4 0
3 years ago
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