All categories

3 years ago

I think its b

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

7 0

Assuming that the rug is rectangular in shape, therefore the formula of area is:

A = l w ---> 1

where l is the length of the rug and w is the width of the rug

We are given that the width of the rug is 5 feet less than the length, therefore:

w = l – 5 ---> 2

Combining equations 1 and 2 and knowing that A = 150 will give us:

l (l – 5) = 150

In the given choices, l = x, therefore:

x (x – 5) = 150

Hence the correct answer is the 1st one (A)

You might be interested in

Pls help me this is really hard

LekaFEV [45]

Answer:Find the area of square and then circle then take them away

Step-by-step explanation:

7 0

2 years ago

Ratio of AC:CB???<br> .———.—————.

erma4kov [3.2K]

Answer:

2:3 I think

Step-by-step explanation:

7 0

2 years ago

Can the sum of two mixed numbers be equal to explain

mel-nik [20]

Answer:no because mixed numbers need atleast a one and a fraction to be mixed number but if there was a fraction then it couldnt equal two because of the 1's

Step-by-step explanation:

8 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

NOW I HAVE MORE, PLZ HELP. IK EVERYONE SAYS THIS BUT PLZZZZZZZ

Kruka [31]

Try to focus the camera man

7 0

2 years ago