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taurus [48]
3 years ago
14

What is the mass of 2.5 mol of ca, which has a molar mass of g/mol

Chemistry
1 answer:
swat323 years ago
3 0
Atomic mass Ca = 40 a.m.u

1 mole Ca ----------- 40 g
2.5 mols Ca -------- ( mass Ca )

Mass Ca = 2.5 x 40 / 1

Mass Ca = 100 / 1

= 100 g of Ca

hope this helps!
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There is 3.58 He in the balloon.
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Determine the mass in grams of each of the following:
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We know, Given mass = Molar mass * Number of moles.

A.) <span>1.25 mol CaF</span>₂

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Molar mass = 78

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B.) 3.4 mol (NH₄)₂SO₄

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In a game of soccer, Jenny kicks the ball straight down the field. Her teammate Craig is waiting close by. He does not allow the
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B. It moves more rapidly in the same direction.

Explanation:

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3 years ago
The standard molar enthalpy of formation of NH3(g) is -45.9 kJ/mol. What is the enthalpy change if 9.51 g N2(g) and 1.96 g H2(g)
Vladimir [108]

Answer:

\Delta H=-29.7kJ

Explanation:

Hello!

In this case, since the undergoing chemical reaction is:

N_2+3H_2\rightarrow 2NH_3

We first need to identify the limiting reactant given the masses of nitrogen and hydrogen:

n_{NH_3}^{by\ H_2}=1.96gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.647molNH_3\\\\  n_{NH_3}^{by\ N_2}=9.51gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.679molNH_3

It means that only 0.647 moles of ammonia are yielded, so the resulting enthalpy change is:

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Best regards!

3 0
3 years ago
A block of substance has a width of 3.8 cm, a length of 8.2 cm, and height of 7 cm . Its mass is 0.68 kg. Calculate the density
satela [25.4K]

Answer:

d = 3.11 g /cm³

Explanation:

Volume -

The volume of a cuboidal object can be calculated by multiplying the length , width and height ,

Hence , Volume ( V ) = l * w * h ,

From the question ,

l = 8.2 cm

w = 3.8 cm

h = 7 cm

Hence, the volume is ,

V = l * w * h

V = 8.2 cm * 3.8 cm * 7 cm

V = 218.12 cm³

Density -

Density of a substance is given as the mass divided by the volume ,

Hence,

d = m / V

From the question,

m = 0.68 kg

since ,

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d = m / V

d = 680 g / 218.12 cm³

d = 3.11 g /cm³

8 0
3 years ago
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