Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0 g of potassium an
1 answer:
Answer:
79.4 kg
Explanation:
The formula for potassium iodide is:-
This means that they are present in the same mole ration, i.e. 1 : 1
Also for 2 samples, the ratio of the masses must be equal .
So,
Thus,
Mass of potassium in sample 1 = 13.0 g
Mass of Iodine in sample 1 = 42.3 g
Mass of potassium in sample 2 = 24.4 kg
Applying in the above formula, we get that:-
Mass of iodine in sample 2 = 79.4 kg
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The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
