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Yakvenalex [24]
3 years ago
14

Which of the following substances are NOT formed by chemical bonds?

Physics
2 answers:
MAVERICK [17]3 years ago
8 0
Pure substance becuase if it is pure it is not a bond
Step2247 [10]3 years ago
3 0

Answer:

The answer is D. pure substance.

Explanation:

A pure substance is a particular class of homogeneous matter whose composition is fixed and chemically defined, that is, it has a stable chemical composition since it is a matter that remains chemically unaltered in its different states of aggregation, endowed with properties singular and characteristic. A pure substance is composed of entities such as molecules, formular units and atoms.

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Arisa [49]

Answer:

can you translate that plz

Explanation:

5 0
3 years ago
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A car starts from rest and speeds up to 30 m/s in a total of 6 s.
sveta [45]
5 m/s
30 divided by 6 is 5
4 0
2 years ago
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If the velocity of a pitched ball has a magnitude of 44.5 m/s and the batted ball's velocity is 55.5 m/s in the opposite directi
Lelu [443]

Answer:

ΔP = 14.5 Ns

I = 14.5 Ns

ΔF = 5.8 x 10³ N = 5.8 KN

Explanation:

The mass of the ball is given as 0.145 kg in the complete question. So, the change in momentum will be:

ΔP = mv₂ - mv₁

ΔP = m(v₂ - v₁)

where,

ΔP = Change in Momentum = ?

m = mass of ball = 0.145 kg

v₂ = velocity of batted ball = 55.5 m/s

v₁ = velocity of pitched ball = - 44.5 m/s (due to opposite direction)

Therefore,

ΔP = (0.145 kg)(55.5 m/s + 44.5 m/s)

<u>ΔP = 14.5 Ns</u>

The impulse applied to a body is equal to the change in its momentum. Therefore,

Impulse = I = ΔP

<u>I = 14.5 Ns</u>

the average force can be found as:

I = ΔF*t

ΔF = I/t

where,

ΔF = Average Force = ?

t = time of contact = 2.5 ms = 2.5 x 10⁻³ s

Therefore,

ΔF = 14.5 N.s/(2.5 x 10⁻³ s)

<u>ΔF = 5.8 x 10³ N = 5.8 KN</u>

4 0
3 years ago
Which of the following describes a situation that would violate the law of entropy?
White raven [17]

Answer:

B. An Iron Bar place in a room becomes cooler than its surroundings.

6 0
2 years ago
With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at
weeeeeb [17]

Answer:

F= 17,075\ N

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

F=m\cdot a

Where m is the mass of the car and a is the acceleration.

F=3,415\ kg\cdot 5\ m/s^2

\boxed{F= 17,075\ N}

3 0
3 years ago
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