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3 years ago

What does it mean when a mineral has a definite chemical composition? Select 2 choices.

Physics

1 answer:

Sergeu [11.5K]3 years ago

8 0

Answer:

Option (2) and (4)

Explanation:

Minerals are the building blocks of rocks and they are comprised of a certain range of chemical substances whose variety of forms and their arrangements are in a preferred orientation.

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An eagle flies from its perch in a tree to the ground to capture and eat its prey. describe its energy transfromation

ddd [48]

10% energy is transferred from the prey to eagle and 90% energy is lost in the enviorment .

7 0

3 years ago

Which is found farthest from the center of an atom?

xxTIMURxx [149]

Electron

Hope this helps

5 0

2 years ago

If a 70-kg swimmer pushes off a pool wall with a force of 250 N what is her acceleration

jek_recluse [69]

F= MA
force equals mass time acceleration
250 N = (70 kg ) (A)
250/70 = 3.5 which is about 4 m/s
Hope this helps

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2 years ago

What is the energy released in this B- nuclear reaction 2K-> 2Ca0,e? (The atomic mass of 42 K is 41.962403 u and that of 42Ca

Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

$_{19}^{42}\textrm{K}\rightarrow _{20}^{42}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{42}\textrm{K}$ = 41.962403 u

Mass of $_{20}^{42}\textrm{Ca}$ = 41.958618 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(41.962403-41.958618)=0.003785u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.003785u)\times c^2$

$E=(0.003785u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=3.526MeV$

Hence, the energy released in the given nuclear reaction is 3.526 MeV.

7 0

3 years ago

A locomotive is pulling 8 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (wi

nikitadnepr [17]

Answer:106560 N

Explanation:

Given

Let Tension between 2 and 3 car be $T_{23}$ and between 3 &4 is $T_{34}$

$T_{23}-T_{34}=ma$

mass of freight car =37,000 kg

acceleration of car $=0.48 m/s^2$

$T_{34}$ is accelerating all freights behind 3

therefore

$T_{34}=5\times ma$

$T_{34}=5\times 37000\times 0.48=88,800 N$

Thus

$T_{23}=T_{34}+ma$

$T_{23}=88,800+37000\times 0.48=88,800+17,760=106560 N$

4 0

3 years ago