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3 years ago

We dont got the force so i got no clue what to do

Physics

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:

work = 1275.3 J

Explanation:

work = (force)(distance)cosø ------- force = ma

=(mass*acceleration)(distance)cosø

=(20*9.81)(6.5)cos0

=1275.3J

nite that the angle of cosine is the difference between the angle of force and the distance. in this case, the force and the distance are in the same direction. :)

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Can someone please help, ty!!<br> (Will mark brainliest)

Alexxandr [17]

28 is balanced and unbalanced

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3 years ago

A 200 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm against the spring, then released. A student wi

Likurg_2 [28]

Answer:

k = 5.05 N/m

Explanation:

In order to calculate the spring mass of the system, you use the following formula:

$T=2\pi \sqrt{\frac{m}{k}}$ (1)

T: period of oscillation of the system

m: mass of the air-track glider = 200g = 0.200 kg

k: spring constant = ?

You first calculate the period of oscillation:

$T=\frac{1}{f}=\frac{1}{12/15.0s}=1.25s$

Next, you solve the equation (1) for k, and then you replace the values of the other parmateres:

$k=4\pi^2 \frac{m}{T^2}\\\\k=4\pi^2 \frac{0.200kg}{(1.25s)^2}=5.05\frac{N}{m}$

The spring constant of the spring is 5.05 N/m

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3 years ago

As a light wave strikes a shiny surface like a piece of polished metal, it will be

ycow [4]

It will reflect because polished metal is like glass or water it’s shiny and smooth

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3 years ago

Find the magnitude: || 5-3i || ...?

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The magnitude would be :

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3 years ago

Help with these three

Elenna [48]

The first: alright, first: you draw the person in the elevator, then draw a red arrow, pointing downwards, beginning from his center of mass. This arrow is representing the gravitational force, Fg.
You can always calculate this right away, if you know his mass, by multiplying his weight in kg by the gravitational constant
$g = 9.81 \frac{m}{s {}^{2} }$
let's do it for this case:
$f_{g} = m \times g \\ f _{g} = 65kg \times 9.81 \frac{m}{s {}^{2} } = 637.65$
the unit of your fg will be in Newton [N]
so, first step solved, Fg is 637.65N
Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
now let's calculate the force of the elevator
$f = m \times a \\ f = 65 \times 5 \frac{m}{s {}^{2} } \\ f = 325n$
so you draw another arrow which is pointing downwards on him, because the elevator is accelating him upwards, making him heavier
the elevator force in this case is a contact force, because it only comes to existence while the two are touching, while Fg is the same everywhere

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3 years ago