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3 years ago

Which of the following ordered pairs lies on the graph of h(x)=-2x squared

Mathematics

1 answer:

Korvikt [17]3 years ago

3 0

Not sure but i think its
<span>‑(2*x^2)</span>

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Consider the equation 5/3v +4 + 1/3v = 8. What is the resulting equation after the first step in the equation?

Fed [463]

I hope this helps you

5+1/3v=8-4

6/3v=4

2/v=4

v=2/4

v=1/2

4 0

3 years ago

some numbers added to -11 is 37.divide this number by -12.then multiply by -8.what is the final number?

LUCKY_DIMON [66]

Since some number added to -11 is 37, we must do 37- (-11), which is 48. Then we check our work and find that 48+-11 is indeed 37. Now we divide 48 by -12, which is -4, multiply by -8 and get a final answer of 32.

6 0

3 years ago

Find the errors and correct the following mathematical sentences.

zhuklara [117]

Answer:

The correct answers are:

xii) (x+7)(x+7)

=x^2 +7x +7x +49

=x^2 +14x +49

xiv) (x+4)(x+2)

=x^2 +2x +4x +8

=x^2 +6x +8

xvi) 5x^3 ÷ 5x^3

6 0

3 years ago

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(worth 100 points) Miguel is organizing his collection of sports memorabilia into glass display cases. He wants to cover each si

AlladinOne [14]

Answer:

4240 inches²

Step-by-step explanation:

In order to find the amount of film needed, we have to find the surface area of this cuboid.

Formula to Find Surface Area of Cuboid: $2(wl+hl+hw)$ , where w = width, l = length, and h = height.

Now, let's solve!

$2(36*25+20*25+20*36)$
$2(900+500+720)$
$2(2120)$
$4240$

Therefore, the answer is 4240 inches².

8 0

2 years ago

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Double angle identity. Just 5 questions. Really need help as my teacher has been frustrated with me

BartSMP [9]

The double angle identities are

$\sin(2x)=2\sin x\cos x$

$\cos(2x)=\cos^2x-\sin^2x$

Then

$2\sin\dfrac\pi6\cos\dfrac\pi6=\sin\left(\dfrac{2\pi}6\right)=\sin\dfrac\pi3$

$\cos^2\dfrac\pi{10}-\sin^2\dfrac\pi{10}=\cos\left(\dfrac{2\pi}{10}\right)=\cos\dfrac\pi5$

The second identity together with the Pythagorean identity, $\sin^2x+\cos^2x=1$ , gives us another equivalent expression:

$\cos^2x-\sin^2x=\cos^2x-(1-\cos^2x)=2\cos^2x-1$

$2\cos^2(0.5)-1=\cos(2\cdot0.5)=\cos1$

4 0

2 years ago

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