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IrinaVladis [17]
4 years ago
7

Which are the solutions of x2 = –7x – 8?

Mathematics
2 answers:
vovangra [49]4 years ago
7 0

Answer:

The solutions are:

x_1=\frac{-7+\sqrt{17}}{2}     x_2=\frac{-7-\sqrt{17}}{2}

Step-by-step explanation:

We have the following quadratic equation

x^2 = -7x - 8

We can rewrite the equation as follows

x^2+7x + 8=0

Now we use the quadratic formula to solve the equation

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case:

a=1,\ b=7,\ c=8

Then:

x=\frac{-7\±\sqrt{7^2-4(1)(8)}}{2(1)}

x=\frac{-7\±\sqrt{49-32}}{2}

x=\frac{-7\±\sqrt{17}}{2}

x_1=\frac{-7+\sqrt{17}}{2}

x_2=\frac{-7-\sqrt{17}}{2}

pishuonlain [190]4 years ago
4 0

Answer:

D on ed :)

Step-by-step explanation:

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3 years ago
As a ship approaches the dock, it forms a 70 angle between the dock and the lighthouse. At the lighthouse, an 80 angle is formed
Trava [24]

Answer:

The distance from the ship to the dock is approximately 5.24 miles

Step-by-step explanation:

From the parameters given in the question, we have;

The angle formed between the dock and the lighthouse = 70°

The angle formed between the dock and the lighthouse at the ship = 80°

The distance between dock and the lighthouse = 5 miles (From a similar question online)

By sine rule, we have;

\dfrac{a}{sin(A)} = \dfrac{b}{sin(B)} = \dfrac{c}{sin(C)}

Therefore, we have;

\dfrac{5}{sin(70^{\circ})} = \dfrac{The \ distance \ from \ the \ ship \ to \ the \ dock}{sin(80^{\circ})}

\therefore The \ distance \ from \ the \ ship \ to \ the \ dock = sin(80^{\circ}) \times \dfrac{5}{sin(70^{\circ})}

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7 0
3 years ago
20 POINTS If the perimeter of a triangle is 14.4. What is the area?
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Answer:

A = 9.9648

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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