Hello,
2(x²+5)=60
<==>x²+5=30 (divided teh 2 members by the positive 5 :keep the equality)
<==>x²-25=0 (substract 25 from 2 members)
<==>(x-5)(x+5)=0 (remarquable product a²-b²=(a+b)(a-b))
<==> x= 5 or x=-5 (a product if null if one at least of its factor is null)
Answer:
73 mph during the second hour!
Step-by-step explanation:
Hour 1=54 mph
Hour 2=? mph
Hour 3=82 mph
Total=209 mph
this means that 209=82+54+?
Simplify it and you will get 73
73 mph
25% of 200 is 50.
25% is also 1/4. So we can do 200(1/4) or 200/4 which is 50.
Answer:
Step-by-step explanation:
Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.
A - the first card is 4
B - second card is ace
We have to find probability for
P(A) = no of 4s in the deck/total cards =
After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it
P(B) = no of Aces in 51 cards/51 =
Hence
(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)