What is the momentum of 200kg portable if it travels 50 meters in 5seconds

1 answer:

5 0

Momentum = mass * velocity

50 meters in 5 seconds = 50/5 = 10 m / second

Required momentum = 200*10 = 2,000

I cant remember how to write the units for this.

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Angle A and angle C are vertical angles. If m∠A=(3x+7)∘ and m∠C=(x+53)∘, what is the value of x

777dan777 [17]

Since it is a given that the angles are vertical, then that means they have to be congruent or = to each other so we can now set up an equation:

3x+7=x+53

Now we need to get the variable alone on one side so subtract 7 from the left (remember what you do, you must do to both sides)

3x=46

Now we can divide by three to get x alone

x=15.333333333 or rounded to 15.33

6 0

3 years ago

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wolverine [178]

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