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Sergio039 [100]
3 years ago
8

What is the momentum of 200kg portable if it travels 50 meters in 5seconds

Mathematics
1 answer:
kvasek [131]3 years ago
5 0
Momentum  = mass * velocity

50 meters in 5 seconds = 50/5  = 10 m / second

Required momentum  = 200*10  = 2,000 

I cant remember how to write the units for this.
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Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),
harkovskaia [24]

Answer:

x^4-3x^3+x^2-4

Step-by-step explanation:

Given the following functions

R(x) = 2x^4 – 3x^3 + 2x – 1 and

C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

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Step-by-step explanation:

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