Answer:
6.25 m/s
Explanation:
Given parameters
Initial mark = 65
Final mark = 15
time taken = 8s
Unknown:
Velocity of the runner = ?
Solution:
Velocity is the displacement divided by time;
Velocity = 
Displacement = Initial mark - final mark = 65 - 15 = 50m
Now, insert the parameters and solve;
Velocity = 
= 6.25m/s
Answer:
The position of the particle is 6m
The velocity of the particle is 16 m/s in negative direction
The acceleration of the object is -40 m/s²
Explanation:
Given;
motion of the particle along a straight line as x = 6 + 4t² - t⁴
The position of the object when t = 2s
x = 6 + 4(2)² - (2)⁴
x = 6 + 16 - 16
x = 6m
The velocity of the object when t = 2s
Velocity = dx/dt
dx/dt = 8t - 4t³
when t = 2s
Velocity = 8(2) - 4(2)³
Velocity = 16 - 32
Velocity = -16m/s
Velocity = 16 m/s (in negative direction)
The acceleration of the object when t = 2s
Acceleration = d²x/dt² = 8 - 12t²
Acceleration = 8 - 12 (2)²
Acceleration = -40 m/s²
<span>5.3 cm/s
This is a matter of conservation of momentum. Since there's no mention of the puck rebounding, I will consider this to be a totally non-elastic collision. So, let's determine the starting momentum of the system.
Goalie is at rest, so his momentum is 0.
Puck is moving at 30.00 m/s with a mass of 0.16 kg, so:
30.00 m/s * 0.16 kg = 4.8 kg*m/s
So the starting momentum is 4.8 kg*m/s moving towards the goal. After the collision, the puck and goalie will have the same momentum. So figure out the mass of the new system:
90.00 kg + 0.16 kg = 90.16 kg
And divide the system momentum by the system mass:
4.8 kg*m/s / 90.16 kg = 0.053238687 m/s
Finally, round to the least precise datum, so the result to 2 significant figures is 0.053 m/s, or 5.3 cm/s.</span>
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Answer:
a
Explanation:
bcz mre than that they will be affected
