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mixas84 [53]
3 years ago
14

3. What are the two types of mixtures?

Physics
1 answer:
ioda3 years ago
7 0

Answer:

heterogeneous and homogeneous

Explanation:

Hetero you can separate whilst homo is combined and cant be separated

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C. The entropy of the system (ice plus water) increases because the process is irreversible.

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You are in a car driving 60 mph without a seat belt. The driver needs to slam on their breaks very hard. At
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A metal ball has a mass of 2kg and a volume of 6 m3. What is its density
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(a) An ideal gas initially at pressure p0 undergoes a free expansion until its volume is 3.80 times its initial volume. What the
trapecia [35]

Answer:

a)P/Po=0.263

b)γ=1.33 So gas is triatomic

c)\dfrac{KE_f}{KE_i}=1.56

Explanation:

a)

initial pressure = Po

Initial volume = Vo

Final volume = 3.8 Vo

Lets take final pressure is P

we know that for free expansion process

PV= Constant

Po x Vo = P x 3.8 Vo

P=0.263 Po

So

P/Po=0.263

b)

Now gas is compressed in adiabatic manner

Final pressure = 1.56 Po

                       =1.56 Po

We know that for adiabatic process

P_1V_1^{\gamma}=P_2V_2^{\gamma}

\dfrac{V_2}{V_1}=\left(\dfrac{P_1}{P_2}\right)^{\dfrac{1}{\gamma}}

0.263P_o(3.8V_o)^{\gamma}=1.56P_o\times V_o^{\gamma}

γ=1.33 So gas is triatomic

c)

We know that average kinetic energy given as

KE=\dfrac{3}{2}KT

\dfrac{KE_f}{KE_i}=\dfrac{T_f}{T_i}\

\dfrac{KE_f}{KE_i}=\dfrac{P_fV_f}{P_iV_i}

\dfrac{KE_f}{KE_i}=\dfrac{1.56P_oV_o}{P_oV_o}

\dfrac{KE_f}{KE_i}=1.56

3 0
3 years ago
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