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antoniya [11.8K]
3 years ago
11

A wagon has a mass of 100 grams and an

Physics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

Net force on the wagon is 200 N

Explanation:

As we know by Newton's II law that net force on the system of mass is given as product of mass and acceleration

Here we know that

mass = 100 kg

a = 2 m/s/s

now we have

F = ma

F = (100)(2)

F = 200 N

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Answer:

y = 80.2 mille

Explanation:

The minimum size of an object that can be seen is determined by the diffraction phenomenon, if we use the Rayleigh criterion that establishes that two objects can be distinguished without the maximum diffraction of a body coincides with the minimum of the other body, therefore so much for the pupil of the eye that it is a circular opening

          θ = 1.22 λ/ d

in a normal eye the diameter of the pupils of d = 2 mm = 0.002 m, suppose the wavelength of maximum sensitivity of the eye λ = 550 nm = 550 10⁻⁹ m

         θ = 1.22 550 10⁻⁹ / 0.002

         θ = 3.355 10⁻⁴ rad

Let's use trigonometry to find the distance supported by this angle, the distance from the moon to the Earth is L = 238900 mille = 2.38900 10⁵ mi

       tan θ = y / L

       y = L tan θ

       y = 2,389 10⁵ tan 3,355 10⁻⁴

       y = 8.02 10¹ mi

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This is the smallest size of an object seen directly by the eye

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3 years ago
You wanted to use your electric grill in your backyard. You need an extension cord. What will be the requirement of your extensi
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Answer:

you need to be able to have long enough to reach and have it far away from things that are going to cause accidents

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Read 2 more answers
What happens to a radioactive isotope as it decays?
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It becomes a different element
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Which scenarios are examples of physical changes? Select three options
pashok25 [27]

Answer:

A kid becoming an adult

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need a picture to answer specific questions.

Explanation:

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The hydraulic oil in a car lift has a density of 8.30 102 kg/m³. The weight of the input piston is negligible. The radii of the
denpristay [2]

Answer:

(a) F_i=68.58\ N

(b) F_i=69.903\ N

Explanation:

Given:

  • density of hydraulic oil, \rho=830\ kg.m^{-3}
  • radius of input piston, r_i=6.3\times 10^{-3}\ m
  • radius of output plunger, r_o=0.125\ m
  • force to be supported, F_o=27000\ N

(a)

<u><em>Condition:</em></u><em>The bottom surfaces of piston and plunger at the same level.</em>

According to Pascal's law the pressure of a fluid is exerted equally in all directions against the walls of its container.

Mathematically:

\frac{F_i}{A_i} =\frac{F_o}{A_o}

putting respective values

\frac{F_i}{\pi\times r_i^2} =\frac{27000}{\pi\times r_o^2}

\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2}

F_i=68.58\ N

(b)

<u><em>Condition:</em></u><em>The bottom surface of the output plunger is 1.30 m above that of the input piston.</em>

Given:

h=1.3\ m

Now,

P_i=P_o+\rho.g.h

\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2} +830\times 9.8\times 1.3

F_i=69.903\ N

7 0
3 years ago
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