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Alona [7]
3 years ago
12

Technician A says that one of advantages of a clutch brake is its ability to bring a vehicle to a halt at low speeds. Technician

B says most current clutch brakes are intended to smooth shifts from neutral to either first or reverse. Who is correct?
A) A only
B) B only
C) Both A and B
Physics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

Option B

Explanation:

  • The advantage of using a clutch brake is that it is capable of handling high load torque and ensures safety at high rotational speeds.
  • The motivation behind a clutch brake is to stop or slow the information shaft from turning, enabling the apparatuses to work without pounding/conflicting. This kills harm to non-synchronized transmissions, and limits the exertion required when moving from impartial into first or switch from a halt.
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hammer [34]

Answer:

the correct answer is option C

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3 years ago
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In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio
Keith_Richards [23]

Answer:

b. 0.25cm

Explanation:

You can solve this question by using the formula for the position of the fringes:

y=\frac{m\lambda D}{d}

m: order of the fringes

lambda: wavelength 500nm

D: distance to the screen 5 m

d: separation of the slits 1mm=1*10^{-3}m

With the formula you can calculate the separation of two adjacent slits:

\Delta y=\frac{(m+1)(\lambda D)}{d}-\frac{m\lambda D }{d}=\frac{\lambda D}{d}\\\\\Delta y=\frac{(500*10^{-9}nm)(5m)}{1*10^{-3}m}=2.5*10^{-3}m=0.25cm

hence, the aswer is 0.25cm

5 0
3 years ago
What property of matter do we consider when deciding whether to buy a half-gallon of milk at the store versus a gallon of milk?
Mrac [35]
Liquified matter maybe.
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3 years ago
Did u poop yet friends or do diehra
Dennis_Churaev [7]

Answer:

ummmm none lol

Explanation:

4 0
3 years ago
Ferns spread spores instead of seeds, and some ferns eject the spores at surprisingly high speeds. One species accelerates 1.4 μ
marta [7]

Answer:

Impulse is 6.3*10^{-9}\:N \cdot s

The average force is 6.3*10^{-6} N

Explanation:

When a mass m undergoes a change in velocity \Delta v, its impulse I is

I =m\Delta v

and if a force F is acting for time t, then the impulse I is given by

I=F*t

Now the mass of the spores in kg is

m=1.4*10^{-6}g*\frac{10^{-3}kg}{g}=1.4*10^{-9}kg

we calculate the impulse from the first formula:

I =m\Delta v =(1.4*10^{-9}kg)(4.5\frac{m}{s} )=6.3*10^{-9}N\cdot s

\boxed{I=6.3*10^{-9}\:N \cdot s}

Now that we have impulse, we calculate the average force on the spore from the second formula:

F=\frac{I}{t} =\frac{6.3*10^{-9}}{1*10^{-3}s}=6.3*10^{-6} N

\boxed{F=6.3*10^{-6} N}

5 0
3 years ago
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