newton's second law helps here.
mass times star velocuty minus mass times end velocity divided by time = force.
short time ,,, hig force
long time lower force ... padding reduces shock ... impulse
Answer:![1.066\times 10^7 m/s](https://tex.z-dn.net/?f=1.066%5Ctimes%2010%5E7%20m%2Fs)
Explanation:
Given
Charge per unit area on each plate(
)=![2.2\times 10^{-7}](https://tex.z-dn.net/?f=2.2%5Ctimes%2010%5E%7B-7%7D)
Plate separation(y)=0.013 m
and velocity is given by
![v^2-u^2=2ay](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ay)
where a=acceleration is given by
![a=\frac{F}{m}=\frac{eE}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF%7D%7Bm%7D%3D%5Cfrac%7BeE%7D%7Bm%7D)
e=charge on electron
E=electric field
m=mass of electron
![E=\frac{\sigma }{\epsilon _0}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B%5Csigma%20%7D%7B%5Cepsilon%20_0%7D)
![a=\frac{e\sigma }{m\epsilon _0}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Be%5Csigma%20%7D%7Bm%5Cepsilon%20_0%7D)
substituting values
![v=sqrt{\frac{2e\sigma y}{m\epsilon _0}}](https://tex.z-dn.net/?f=v%3Dsqrt%7B%5Cfrac%7B2e%5Csigma%20y%7D%7Bm%5Cepsilon%20_0%7D%7D)
![v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 2.2\times 10^{-7}\times 0.013}{9.1\times 10^{-31}\times 8.85\times 10^{-12}}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%202.2%5Ctimes%2010%5E%7B-7%7D%5Ctimes%200.013%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%7D%7D)
![v=1.066\times 10^7 m/s](https://tex.z-dn.net/?f=v%3D1.066%5Ctimes%2010%5E7%20m%2Fs)
Answer:
x = 0.0756 m
Fred moves in the direction where Brutus moves
Explanation:
This exercise is for the moment, we define the system as formed by the two players, for this system the forces in the clash are internal, so the moment is preserved
Initial. Before the crash
p₀ = m v₀₁ - M v₀₂
Final. After the crash
= (m + M) v
p₀ = ![p_{f}](https://tex.z-dn.net/?f=p_%7Bf%7D)
m v₀₁ –M v₀₂ = (m + M) v
v = (m v₀₁ - M v₀₂) / (m + M)
Let's calculate
v = (60 6 - 120 4) / (60 +120)
v = - 120/180
v = - 0.667 m / s
The negative sign indicates that the final speed is the direction where Brutus runs
Let's use Newton's second law to find the acceleration of the two players
fr = (m + M) a
fr = μ N
N- W = 0
N = (m + M) g
μ (m + M) g = (m + M) a
a = μ g
a = 0.30 9.8
a = 2.94 m / s²
We use kinematics to find the distance traveled, the final speed is zero
v² = v₀² - 2 a x
x = v₀² / 2 a
x = 0.667² / (2 2.94)
x = 0.0756 m
The correct answer is - federal government system.
Even though all of the countries in the European Union are separate countries and they all have their own governments, still the European Union has authority over them. The European Union has its own parliament, and one of the main conditions for every country member is that it obliges to respect and implement the decisions of this parliament, thus losing little of their sovereignty in the process. This is pretty much the same principle used in the federal government systems, where all states have their own leaders and have big authority in their own borders, but also have to obey the commands and decisions of the central government.
Answer : The time required is, 16.1 minutes.
Explanation :
First we have to calculate the amount of heat required to increase the temperature is:
![Q=mC\Delta T\\\\Q=\rho VC\Delta T](https://tex.z-dn.net/?f=Q%3DmC%5CDelta%20T%5C%5C%5C%5CQ%3D%5Crho%20VC%5CDelta%20T)
![(m=\rho V)](https://tex.z-dn.net/?f=%28m%3D%5Crho%20V%29)
where,
Q = amount of heat required = ?
m = mass
= density of air = ![1.20kg/m^3](https://tex.z-dn.net/?f=1.20kg%2Fm%5E3)
V = volume of air
C = specific heat of air = ![1006J/kg^oC](https://tex.z-dn.net/?f=1006J%2Fkg%5EoC)
= change in temperature = ![10.0^oC](https://tex.z-dn.net/?f=10.0%5EoC)
Now put all the given values in above formula, we get:
![Q=\rho VC\Delta T](https://tex.z-dn.net/?f=Q%3D%5Crho%20VC%5CDelta%20T)
![Q=(1.20kg/m^3)\times (3.00m\times 5.00m\times 8.00m)\times (1006J/kg^oC)\times (10.0^oC)](https://tex.z-dn.net/?f=Q%3D%281.20kg%2Fm%5E3%29%5Ctimes%20%283.00m%5Ctimes%205.00m%5Ctimes%208.00m%29%5Ctimes%20%281006J%2Fkg%5EoC%29%5Ctimes%20%2810.0%5EoC%29)
![Q=1.449\times 10^6J](https://tex.z-dn.net/?f=Q%3D1.449%5Ctimes%2010%5E6J)
Now we have to calculate the time required.
Formula used :
![t=\frac{Q}{P}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7BQ%7D%7BP%7D)
where,
t = time required = ?
Q = amount of heat required = ![1.449\times 10^6J](https://tex.z-dn.net/?f=1.449%5Ctimes%2010%5E6J)
P = power = 1500 W
Now put all the given values in above formula, we get:
![t=\frac{1.449\times 10^6J}{1500W}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B1.449%5Ctimes%2010%5E6J%7D%7B1500W%7D)
![t=966s\times \frac{1min}{60s}=16.1min](https://tex.z-dn.net/?f=t%3D966s%5Ctimes%20%5Cfrac%7B1min%7D%7B60s%7D%3D16.1min)
Thus, the time required is, 16.1 minutes.