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VashaNatasha [74]
3 years ago
5

An object is moving to the right in a straight line. The net force acting on the object is also directed to the right, but the m

agnitude of the force is decreasing with time. The object will
A) continue to move to the right, with its speed increasing with time.
B) continue to move to the right, with its speed decreasing with time.
C) continue to move to the right with a constant speed.
D) stop and then begin moving to the left.
Physics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

A) continue to move to the right, with its speed increasing with time.

Explanation:

As long as force is positive , even when it is decreasing , it will create positive increase in velocity . Hence the body will keep moving with increasing velocity towards the right . The moment the force becomes zero on continuously decreasing , the increase in velocity stops and the body will be moving with the last velocity uniformly towards right . When the force acting on it becomes negative , even then the body will keep on going to the right till negative force makes its velocity zero . D uring this period , the body will keep moving towards right with decreasing velocity .

Hence in the present case A , is the right choice.

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An object is thrown 16m/s straight up from a 7m tall cliff. How much time does it take to hit the ground below
harkovskaia [24]

Answer:

0,54 sec

Explanation:

t=s/v

t=7/13 s=0,54sec

5 0
3 years ago
Which of the following is an effect of the electric force?
stich3 [128]

As we know that two charges exert force on each other when they are placed near to each other

The force between two charges is given as

F = \frac{kq_1q_2}{r^2}

here we know that

q_1, q_2 = two different point charges

r = distance between two point charges

also we know that two similar charges always repel each other while two opposite charges always attract each other

so here correct answer would be

<em>A. A positive and negative charge attract each other.</em>

6 0
3 years ago
Read 2 more answers
A moving particle encounters an external electric field that decreases its kinetic energy from 9520 eV to 7060 eV as the particl
Sati [7]

Given Information:

KEa = 9520 eV

KEb = 7060 eV

Electric potential = Va = -55 V

Electric potential = Vb = +27 V

Required Information:

Charge of the particle = q = ?

Answer:

Charge of the particle = +4.8x10⁻¹⁸ C

Explanation:

From the law of conservation of energy, we have

ΔKE = -qΔV

KEb - KEa = -q(Vb - Va)

-q = KEb - KEa/Vb - Va

-q = 7060 - 9520/27 - (-55)

-q = 7060 - 9520/27 + 55

-q = -2460/82

minus sign cancels out

q = 2460/82

Convert eV into Joules by multiplying it with 1.60x10⁻¹⁹

q = 2460(1.60x10⁻¹⁹)/82

q = +4.8x10⁻¹⁸ C

6 0
4 years ago
8. What is the frequency of green light waves that have a wavelength of 5.2 x 10-7 m.? The speed of light is 3.0 x 108 m/s
o-na [289]

Answer:

f=5.76\times 10^{14}\ Hz

Explanation:

We need to find the frequency of green light having wavelength o5.2\times 10^{-7}\ m. It can be calculated as follows :

c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz

So, the required frequency of green light is equal to 5.76\times 10^{14}\ Hz.

4 0
3 years ago
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 45.
SpyIntel [72]

Answer:

Torque on the rocket will be 1.11475 N -m

Explanation:

We have given that muscles generate a force of 45.5 N

So force F = 45.5 N

This force acts on the is acting on the effective lever arm of 2.45 cm

So length of the lever arm d = 2.45 cm = 0.0245 m

We have to find torque

We know that torque is given by \tau =F\times d=45.5\times 0.0245=1.11475N-m

So torque on the rocket will be 1.11475 N -m

3 0
3 years ago
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