Answer:
Explanation:
Single-phase transformers can operate to either increasing or decreasing the voltage applied to the primary winding. When a transformer is used to “increase” the voltage on the secondary winding with respect to the primary, it is called a Step-up transformer
Answer:
![Q=23,430J](https://tex.z-dn.net/?f=Q%3D23%2C430J)
Explanation:
Hello,
In this case, since we compute the required energy via:
![Q=mC\Delta T](https://tex.z-dn.net/?f=Q%3DmC%5CDelta%20T)
Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:
![\Delta T=100-20=80\°C](https://tex.z-dn.net/?f=%5CDelta%20T%3D100-20%3D80%5C%C2%B0C)
Therefore, the energy turns out:
![Q=70g*4.184\frac{J}{g\°C}*80\°C\\ \\Q=23,430J](https://tex.z-dn.net/?f=Q%3D70g%2A4.184%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%2A80%5C%C2%B0C%5C%5C%20%5C%5CQ%3D23%2C430J)
Best regards.
To solve this problem we will apply the concepts related to energy conservation. From this conservation we will find the magnitude of the amplitude. Later for the second part, we will need to find the period, from which it will be possible to obtain the speed of the body.
A) Conservation of Energy,
![KE = PE](https://tex.z-dn.net/?f=KE%20%3D%20PE)
![\frac{1}{2} mv ^2 = \frac{1}{2} k A^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%20%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20k%20A%5E2)
Here,
m = Mass
v = Velocity
k = Spring constant
A = Amplitude
Rearranging to find the Amplitude we have,
![A = \sqrt{\frac{mv^2}{k}}](https://tex.z-dn.net/?f=A%20%3D%20%5Csqrt%7B%5Cfrac%7Bmv%5E2%7D%7Bk%7D%7D)
Replacing,
![A = \sqrt{\frac{(0.750)(31*10^{-2})^2}{13}}](https://tex.z-dn.net/?f=A%20%3D%20%5Csqrt%7B%5Cfrac%7B%280.750%29%2831%2A10%5E%7B-2%7D%29%5E2%7D%7B13%7D%7D)
![A = 0.0744m](https://tex.z-dn.net/?f=A%20%3D%200.0744m)
(B) For this part we will begin by applying the concept of Period, this in order to find the speed defined in the mass-spring systems.
The Period is defined as
![T = 2\pi \sqrt{\frac{m}{k}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bm%7D%7Bk%7D%7D)
Replacing,
![T = 2\pi \sqrt{\frac{0.750}{13}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7B0.750%7D%7B13%7D%7D)
![T= 1.509s](https://tex.z-dn.net/?f=T%3D%201.509s)
Now the velocity is described as,
![v = \frac{2\pi}{T} * \sqrt{A^2-x^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BT%7D%20%2A%20%5Csqrt%7BA%5E2-x%5E2%7D)
![v = \frac{2\pi}{T} * \sqrt{A^2-0.75A^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BT%7D%20%2A%20%5Csqrt%7BA%5E2-0.75A%5E2%7D)
We have all the values, then replacing,
![v = \frac{2\pi}{1.509}\sqrt{(0.0744)^2-(0.750(0.0744))^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B1.509%7D%5Csqrt%7B%280.0744%29%5E2-%280.750%280.0744%29%29%5E2%7D)
![v = 0.2049m/s](https://tex.z-dn.net/?f=v%20%3D%200.2049m%2Fs)
Answer:
13807.2 J/g°C
Explanation:
I just took the test and got it correct
Steaming the egg
The heat is conduction through the pan and into the water
There is convection current in the water and the pot
The heat is radiated from the water to the egg