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nordsb [41]
3 years ago
7

The emission spectrums are known for the elements below. Line spectra for boron, lithium, hydrogen, helium, potassium and unknow

n sample. Boron has 3 purple lines, 1 blue line, 2 blue-green lines and 2 orange lines. Lithium has 2 purple lines, 2 blue lines, 2 blue-green lines, 1 orange line and 1 red line. hydrogen has one line of each purple, blue, blue-green and red. helium has 3 purple lines, 3 blue lines, 3 blue-green lines 1 yellow line and 2 red lines. Potassium has 8 purple lines, 6 blue-green lines, 10 green lines, 3 yellow lines, 2 orange lines and 6 red lines. The unknown sample has Potassium has 8 purple lines, 6 blue-green lines, 10 green lines, 3 yellow lines, 2 orange lines and 6 red lines. What elements are in the unknown sample? Check all that apply. boron lithium hydrogen helium potassium
Chemistry
2 answers:
Montano1993 [528]3 years ago
8 0

Answer:

E

Explanation:

nata0808 [166]3 years ago
7 0

Answer:

The Answer is (B) lithium and (E) potassium

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In this reaction what is the correct coefficient for sodium chloride? pb(no3)2 ? nacl → pbcl2 ? nano3
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<span>pb(no3)2 + 2 nacl → pbcl2 + 2nano3</span>
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4 years ago
A scientist has a container with a substance inside. At first, the molecules in the substance move away from each other. Later,
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Answer:

Base on the properties the substances possess the substance change phase from gas to liquid.

Explanation:

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5 0
3 years ago
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The answer is 600. A sample of C3H8O which contains two hundred molecules, it also holds six hundred carbon atoms. A carbon atom holds six electrons, four of its electrons are found in its valence shell or also known as its outer shell.

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-Dominant- [34]

Answer:

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Explanation:

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That means, for a complete reaction of an amount of barium nitrate you must add the same amount in moles of sodium sulfate. To solve this problem we need to convert the mass of barium nitrate to moles = Moles of sodium sulfate that must be added:

<em>Moles Ba(NO₃)₂ -Molar mass: 261.3g/mol-:</em>

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<em>Mass Na₂SO₄ -Molar mass: 142.04g/mol-:</em>

0.287 moles * (142.04g / mol) =

<h3>40.8g of sodium sulfate must be added</h3>
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