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nordsb [41]
2 years ago
7

The emission spectrums are known for the elements below. Line spectra for boron, lithium, hydrogen, helium, potassium and unknow

n sample. Boron has 3 purple lines, 1 blue line, 2 blue-green lines and 2 orange lines. Lithium has 2 purple lines, 2 blue lines, 2 blue-green lines, 1 orange line and 1 red line. hydrogen has one line of each purple, blue, blue-green and red. helium has 3 purple lines, 3 blue lines, 3 blue-green lines 1 yellow line and 2 red lines. Potassium has 8 purple lines, 6 blue-green lines, 10 green lines, 3 yellow lines, 2 orange lines and 6 red lines. The unknown sample has Potassium has 8 purple lines, 6 blue-green lines, 10 green lines, 3 yellow lines, 2 orange lines and 6 red lines. What elements are in the unknown sample? Check all that apply. boron lithium hydrogen helium potassium
Chemistry
2 answers:
Montano1993 [528]2 years ago
8 0

Answer:

E

Explanation:

nata0808 [166]2 years ago
7 0

Answer:

The Answer is (B) lithium and (E) potassium

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The cis and trans geometric isomers of a compound have different chemical and physical properties. Draw the structure of the geo
frutty [35]

<u>Answer:</u> The structure of the geometrical isomers are attached below.

<u>Explanation:</u>

Cis- and Trans- isomers are the geometrical isomers which have same chemical formula but different structural formula

According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.

If the highest priority groups are on the same side, it is known as cis-form and if the highest priority groups are on opposite side, it is known as trans-form.

We are given a chemical compound, which is 2-pentene.

In this the highest priority groups are methyl and ethyl groups.

When the groups are on the same side, it forms cis-form and when the groups are on the opposite side, it forms trans-form

The structure of the geometrical isomers are attached below.

7 0
2 years ago
Does SiF4 have polar covalent bonds?
Kamila [148]

Answer:

SiF4 is not a polar covalent bond.

Explanation:

SiF4 is a nonpolar molecule because the fluorine's are arranged around the central silicon atom in a tetrahedral molecule with all of the regions of negative charge cancelling each other out.

8 0
3 years ago
Thre largest source of available freshwater on earth is
Burka [1]
Ice caps so it would be D

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6 0
3 years ago
Read 2 more answers
Draw one of the stereoisomers of the product formed when benzaldehyde (c6h5cho) is treated with ph3p═chcooch3.
8_murik_8 [283]
This reaction is known as Wittig Reaction. A powerful reaction for the synthesis of Alkene. In question the starting materials are aldehyde and a Phosphorous Ylide. Ylide when reacted with aldehyde produces a four membered ring which on rearrangement gives Alkene and triphenylphosphine oxide. Phosphorous having great affinity toward the oxygen is the driving force of this rearrangement. The reaction along with product (highlighted blue) is as follow,

8 0
3 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

7 0
3 years ago
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