How many grams are in 1.60 moles Hg(NO3)2
1 answer:
You might be interested in
Complete Question
A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.
Answer:
Explanation:
From the question we are told that:
Heat Capacity
Mass of water
Initial Temperature of Aluminium
Initial Temperature of Water
Final Temperature of Water
Generally
Heat loss=Heat Gain
Therefore
The final temperature : 78.925°C
<h3>Further explanation </h3>Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Energy releases = 130 kcal = 130 x 4.18 kJ=543.4 kJ
The final temperature :
Final temperature :
ΔT=final-initial
51.925°c=final-27°c
final = 51.925+27=78.925°C