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3 years ago

Is petrol hard to make

Chemistry

1 answer:

AnnyKZ [126]3 years ago

8 0

i belive it is hard to make

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35.7 L of CL2 gas are used in an experiment. Determine the mass in grams of the chlorine gas

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3 years ago

How does wavelength affect the pitch of a sound?

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2 years ago

List three examples of waves that can transfer energy without going through a medium

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2 years ago

If the energy difference between two electronic states is 214.68 kJ / mol , calculate the frequency of light emitted when an ele

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${\qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

Energy difference btween the two electronic states can be expressed as :

${ \qquad \sf \dashrightarrow \: \Delta E = h\nu}$

[ h = planks constant, ${\: \nu }$ = frequency ]

$\qquad \sf \dashrightarrow \:214.68 = 39.79 \times 10 {}^{ - 14} \times \nu$

$\qquad \sf \dashrightarrow \: \nu = \cfrac{214.68}{39.79 \times 10 {}^{ - 4} }$

$\qquad \sf \dashrightarrow \: \nu = \cfrac{214.68}{39.79 } \times 10 {}^{14}$

$\qquad \sf \dashrightarrow \: \nu \approx 5.395 \times10 {}^{14} \:\:hertz$

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1 year ago

Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart

bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

$C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)$

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion) and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = $156.31 g/mol.$

$\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.$

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

$V = \frac{nRT}{P} \\$

$V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\$

$V = 428.23 \ L$

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3 years ago