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Alexus [3.1K]
3 years ago
9

Help asap for brainlist

Chemistry
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

True po

Explanation:

Sana nakatutulong

#Carry on learning

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How can exposoure to high energy waves be both harmful and helpful to cells??
belka [17]
Exposure to high energy waves can be helpful to cells by damaging DNA in cells, meaning if somebody were to have cancer cells it breaks down the bad cells and it can shrink tumor. It can be harmful by damaging skin cells, which we need as our first line of defense. Meaning, it could cause skin cancer. Hope this helped!
3 0
3 years ago
What kind of intermolecular forces act between two ammonia molecules
iragen [17]

Answer:

extensive hydrogen bonding

Explanation:

The high boiling points of water, hydrogen fluoride (HF) and ammonia (NH3) is an effect of the extensive hydrogen bonding between the molecules. The London dispersion force is caused by random and temporary changes in the polarity of atoms, caused by the location of the electrons in the atoms' orbitals.

Hope this helps :)

6 0
2 years ago
Which has a greater amount of particles, 1.00 mole of hydrogen (H) or 1.00 moles of oxygen(0)?
Bas_tet [7]

Answer:

Both have the same amount of particles.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ particles.

This implies that 1 mole of Hydrogen contains 6.02×10²³ particles. Also, 1 mole of oxygen contains 6.02×10²³ particles.

Thus, 1 mole of Hydrogen and 1 mole of oxygen contains the same number of particles.

7 0
3 years ago
2A1 +3CL2, → 2AICI3 what is the reaction
DerKrebs [107]

Answer:

redox reaction

Explanation:

8 0
3 years ago
Read 2 more answers
Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and t
Talja [164]
<span>(a) what is the average volume (in cubic meters) required for each iron atom
For this case, the density of Iron would be </span>7.87g/cm³
<span>
V = 9.27 x 10^-26 kg / </span>7.87g/cm<span>³ ( 1 kg / 1000 g)
</span>V = 1.18 x 10-23 cm³<span>

(b) what is the distance (in meters) between the centers of adjacent atoms?
We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.

V = </span>1.18 x 10-23 cm<span>³ = s</span>³
s = 2.28 x 10^-8 cm
7 0
3 years ago
Read 2 more answers
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