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Alexus [3.1K]
2 years ago
9

Help asap for brainlist

Chemistry
1 answer:
Brums [2.3K]2 years ago
7 0

Answer:

True po

Explanation:

Sana nakatutulong

#Carry on learning

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A sample of a pure element has a mass of 45.6g and contains 4.19 x 10 23 atoms. Identify the element.
max2010maxim [7]
<h2>Answer:</h2>

    ZINC

<h2>Explanation:</h2>

<em>To identify the element based on the informartion given, we have to find the molar mass since this mass is unique to each element.</em>

            Molar mass = mass ÷ moles

<em>We already know the mass based on the question, as such we now need to find the # of moles.</em>

           Since 1 mole contains 6.02214 × 10²³ atoms

      then let  x moles contain 4.19 × 10²³ atoms <em>(given in the question)</em>

<em>     </em><em> </em>   ⇒   x =  (4.19 × 10²³ atoms  ×  1 mol) ÷ 6.02214 × 10²³ atoms

              x  =  0.69577 mol

<em>Now that we have the moles we can substitute it into the molar mass equation and solve for the molar mass.</em>

           ⇒ molar mass = 45.6 g ÷ 0.69577 mol

           ⇒ molar mass ≈  65.54 g/mol

                    This molar mass is closest to that of ZINC.

7 0
3 years ago
An environmental scientist developed a new analytical method for the determination of cadmium (cd^2+) in mussels. To validate th
Anettt [7]

Answer:

The method is accurate  in the calculation of the Cu^+2

Explanation:

As a first step we have to calculate the <u>average concentration </u>of Cu^+2 find it by the method.

\frac{0.782+0.762+0.825+0.838+0.761 }{5} =0.79 ppm

Then we have to find the<u> standard deviation:</u>

s=\sqrt{\frac{1}{N-1}\sum_{i=1}^N(x_i-\bar{x})^2}=0.0359

For the confidence interval we have to use the formula:

μ=Average±\frac{t*s}{\sqrt{n} }

Where:

t=t student constant with 95 % of confidence and 5 data=2.78

μ= 0.79  ±  \frac{2.78*0.0359}{\sqrt{5} }

upper limit:  0.84

lower limit: 0.75

If we compare the limits of the value obtanied by the method (Figure 1 Red line) with the reference material (Figure 1 blue line) we can see that the values obtained by the method are within the values suggested by the reference material. So, it's method is accurate.

7 0
3 years ago
How many particles are present in 10.0 moles of table salt?
Dima020 [189]

1.01 x 10^24 molecules.

Explanation:

To calculate the number of molecules in a given number of mole, we can simply multiply by Avogadro's number which is equal to 6.022 x 10 ^23.

Therefore,

10 molecules = 1.68 mol x (6.022 x 10^23 molecules) / (1 mol = 1.01 x 10^24) molecules.

I hope this helps :)

7 0
2 years ago
Studio
coldgirl [10]

Answer:

0.895 g/mL

Explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

2.763 lb \times \frac{453.59 g}{1lb} = 1,253g

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

5.93cup \times \frac{236.59mL}{1cup} = 1.40 \times 10^{3} mL

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

\rho = \frac{m}{V} = \frac{1,253g}{1.40 \times 10^{3}mL  } = 0.895 g/mL

4 0
3 years ago
Need Help!!! What else should I write?
alexira [117]
You should write to make it a different way like with eye contact solution, laundry detergent, etc. You could also write to see if lotion would have an affect on the expandable-ness
4 0
3 years ago
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