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3 years ago

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Chemistry

1 answer:

Brums [2.3K]3 years ago

7 0

Answer:

True po

Explanation:

Sana nakatutulong

#Carry on learning

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How many grams of solid barium sulfate form when 25.0 ml of 0.160 m barium chloride reacts with 68.0 ml of 0.055 m sodium sulfat

GalinKa [24]

Hope this will help you.

8 0

3 years ago

The molar mass of barium nitrate (ba(no3)2) is 261.35 g/mol. what is the mass of 5.30 × 1022 formula units of ba(no3)2? 0.0900 g

liberstina [14]

Molar mass is the ratio of the mass to that amount of the substance. The mass of the barium nitrate in the formula unit is 23.0 grams.

The mass of a substance is the product of the molar mass of the compound and the number of moles of the compound.

Given,

Molar mass of barium nitrate = 261.35 g/mol

If, $6.022 \times 10^{23}$ have a mass of 261.35 g/mol then, $5.30 \times 10^{22}$ formula units will have a mass of,

$\begin{aligned}& = \dfrac{261.35 \times 5.30 \times 10^{22}}{6.022\times 10^{23}}\\\\&= 23.0\;\rm gm\end{aligned}$

Therefore, option C. 23.0 gm is the mass of barium nitrate.

Learn more about mass here:

brainly.com/question/24958554

6 0

2 years ago

Cuando un gas que se encuentra a 20°c se calienta hasta los 40°c sin que varie su presion, su volumen se duplica

kati45 [8]

Answer:

Not doubled

Explanation:

The equation below represent the ideal gases relationship

PV ÷ T = constant

Here

P denotes pressure,

V denotes volume,

T denotes temperature in degrees Kelvin

Now

20 ° c = 273 + 20

= 293 K

And,

40 ° c = 313 K

So,

V = Vo. 313 K ÷ 293 K = 1.07 Vo

So, the volume is NOT doubled.

In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero

4 0

3 years ago

What is the molarity of an H3PO4solution if 15.0 mL is completely neutralized by 38.5 mL of 0.150 MNaOH? Please explain your ans

rodikova [14]

Answer:

M=Molarity

V=volume

change millilitre to litre

so:15ml=0.015 L

:38.5ml=0.0385 L

M1V1=M1V1

M1* 0.015 L= 0.15M*0.0385 L

M1=0.00385

8 0

3 years ago

a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill

baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRT$

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0

3 years ago