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sammy [17]
3 years ago
7

A block made of a certain material has a thickness of 20 cm and a thermal conductivity of 0.04 m C. At a particular instant in t

ime the temperature distribution with x, the distance from the left surface of the block, is T =-100 x2 + 20 x, where x is in meter. Calculate the heat flux at the left (x = 0) and right face of the block.
Chemistry
1 answer:
amid [387]3 years ago
8 0

Answer:

heat flux ( Q ) = 8 W/m³ uniform heat flux throughout the block

Explanation:

flat plate ecuation with uniform source:

  • d2T / dx² = - Q / k...........from general balance
  • if x = 0 ⇒ dT / dx = 0 ; Q = 0
  • if x = L ⇒ T = T1

∴ k = 0.04 W/mC;   L = 0.2 m

If T = - 100x² + 20x

⇒ dT / dx = - 200x + 20

⇒ d2T / dx² = - 200 = - Q / k

⇒ Q / k = 200

⇒ Q = 200 * 0.04 W/mC

⇒ Q = 8 W/m³

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Explanation:
Use the following equation:
q
=
m
c
Δ
T
,
where:
q
is heat energy,
m
is mass,
c
is specific heat capacity, and
Δ
T
is the change in temperature.
Δ
T
=
T
final
−
T
initial
Known
m
=
125 g
c
Pb
=
0.130
J
g
⋅
∘
C
T
initial
=
17.5
∘
C
T
final
=
42.1
∘
C
Δ
T
=
42.1
∘
C
−
17.5
∘
C
=
24.6
∘
C
Unknown
q
Solution
Plug the known values into the equation and solve.
q
=
(
125
g
)
×
(
0.130
J
g
⋅
∘
C
)
×
(
24.6
∘
C
)
=
400. J

(rounded to three significant figures)
Convert Joules to calories
1 J
=
0.2389 cal
to four significant figures.
400
.
J
×
0.2389
cal
1
J
=
95.6 cal

(rounded to three significant figures)
95.6 cal
are needed.
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