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tia_tia [17]
4 years ago
11

) A 100-g ball falls from a window that is 12 m above ground level and experiences no significant air resistance as it falls. Wh

at is its momentum when it strikes the ground?
Physics
1 answer:
yawa3891 [41]4 years ago
3 0

Answer:

Momentum = 1.534 kgm/s

Explanation:

Using the equations of motion, we can obtain the velocity of the ball as it hits the ground.

g = 9.8 m/s²

y = 12 m

u = initial velocity = 0 m/s, since the ball was released from rest

v = final velocity befor the ball hits the ground.

v² = u² + 2ay

v² = 0 + 2×9.8×12 = 235.2

v = 15.34 m/s

The momentum at any point is given as mass × velocity at that point

Mass = 100 g = 0.1 kg, velocity = 15.34 m/s

Momentum = 0.1 × 15.34 = 1.534 kgm/s

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True or false: the energy that is related to moving parts is called electrical energy
NemiM [27]

False, that would be kinetic energy.

3 0
3 years ago
To what circuit element is an ideal capacitor equivalent in circuits for which the currents and voltages are constant with time?
Vanyuwa [196]

Explanation:

Since the current flowing through an ideal capacitor is described by equation:

i_{C}=C\frac{dV}{dt}

for voltage across the capacitor constant with time the current is:

i_{C}=\frac{d(Constant)}{dt}=0

Open switch has this characteristics (Constant voltage and zero current).  

3 0
3 years ago
A string with a mass density of 3 * 10^-3 kg/m is under a tension of 380 N and is fixed at both ends. One of its resonance frequ
Delvig [45]

Answer:

(a) the fundamental frequency of this string is 65 Hz

(b) the harmonics of the given frequencies are third and fourth respectively.

(c) the length of the string is 2.74 m

Explanation:

Given;

mass density of the string, μ = 3 x 10⁻³ kg/m

tension of the string, T = 380 N

resonating frequencies, 195 Hz and 260 N

For the given resonant frequencies;

195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } ---(1)\\\\260 = \frac{n+1}{2l} \sqrt{\frac{T}{\mu} } ---(2)\\\\divide \ (2) \ by (1)\\\\\frac{260}{195} = \frac{n+1 }{n} \\\\260n = 195(n+1)\\\\260 n = 195 n + 195\\\\260n - 195n = 195\\\\65n = 195\\\\n = \frac{195}{65} \\\\n = 3

(c) From any of the equations, solve for Length of the string (L);

195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } \\\\195 = \frac{3}{2l}\sqrt{\frac{380}{3\times 10^{-3}} } \\\\l = \frac{3}{2\times 195}\sqrt{\frac{380}{3\times 10^{-3}} }\\\\l = 2.74 \ m

(a) the fundamental frequency is calculated as;

f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 2.74} \sqrt{\frac{380}{3\times 10^{-3} } }\\\\f_o =  65 \ Hz

(b) harmonics of the given frequencies;

the first harmonic (n = 1) = f₀ = 65 Hz

the second harmonic (n = 2) = 2f₀ = 130 Hz

the third harmonic (n = 3) = 3f₀ = 195 Hz

the fourth harmonic (n = 4) = 4f₀ = 260 Hz

Thus, the harmonics of the given frequencies are third and fourth respectively.

7 0
3 years ago
which of these waves requires a medium to travel through light wave electromagnetic waves sound wave microwave
navik [9.2K]
Sound waves require a medium to travel through. :D 
7 0
4 years ago
Read 2 more answers
A stack of 1500 bricks covers a ground area of 2.750m by 1.350m.the average mass of bricks is 3.200kg.calculate the total force
lozanna [386]

The total force on the ground due to the bricks is 47,040 N.

<h3>Total force on the ground</h3>

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

  • Fₙ is normal force
  • m is mass of the brickes
  • g is acceleration due to gravity

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

Learn more about total force here: brainly.com/question/14361879

#SPJ1

5 0
2 years ago
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