Question

How many sulfur atoms are in 0.45 mol BaSO4??

Answer 1

Explanation:

According to the mole concept, there are $6.022 \times 10^{23}$ atoms present in one mole.

As it is given that number of moles of $BaSO_{4}$ are 0.45 mol.

Therefore, there is only one atom of sulfur. Hence, calculate atoms of sulfur as follows.

                $1 \times 0.45 \times 6.022 \times 10^{23}$ atoms

                      = $2.709 \times 10^{23}$ atoms

Thus, we can conclude that there are $2.709 \times 10^{23}$ atoms of sulfur in 0.45 mol $BaSO_{4}$.

Answer 2

$(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}$