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pashok25 [27]
3 years ago
15

Hi do you know this?​

Chemistry
2 answers:
tankabanditka [31]3 years ago
8 0
It’s the second answer choice
AURORKA [14]3 years ago
6 0

Answer:

2

Explanation

It seems logical

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Identify the number of protons, neutrons, and electrons in a neutral atom of each of the following (you can refer to a periodic
Delvig [45]
You must first know that the number of protons and neutrons are same, and neutrons number may vary. Carbon 12 has 6 protons, 6 neutrons and 6 electrons. Sodium 23 has 12 protons , 12 electrons and and 11 neutrons. Silver 108 has 47 protons, 47 electrons and 61 electrons. Finally, Sulfur 32 has 16 protons, 16 nuetrons and 16 electrons. Basically the number of neutrons in an atom can be found by subtracting proton number from mass number
7 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
3 years ago
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Answer:

ok

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(answer is from go0gle not gonna say its lie)

6 0
2 years ago
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