Question

The decomposition of potassium chlorate yields oxygen gas. If the yield is 895%, how many grams of KClO3 are needed to produce 10.0 L of O2 ?
2KClO3(s) -- > 2KCl(s) + 3 O2(g)

Answer 1

The answer is either 38 g or 40.g KCLO3. If it 95% instead of 895%.