Answer:
- A'(4, -4)
- B'(0, -3)
- C'(2, -1)
- D'(3, -2)
Step-by-step explanation:
The coordinate transformation for a 270° clockwise rotation is the same as for a 90° counterclockwise rotation:
(x, y) ⇒ (-y, x)
The rotated points are ...
A(-4, -4) ⇒ A'(4, -4)
B(-3, 0) ⇒ B'(0, -3)
C(-1, -2) ⇒ C'(2, -1)
D(-2, -3) ⇒ D'(3, -2)
_____
<em>Additional comment</em>
To derive and/or remember these transformations, it might be useful to consider where a point came from when it ends up on the x- or y-axis.
A point must have come from the -y axis if rotating it 270° CW makes it end up on the +x-axis. A point must have come from the x-axis if rotating it 270° makes it end up on the +y axis. That is why we write ...
(x, y) ⇒ (-y, x) . . . . . . the new x came from -y; the new y came from x
Answer:
4
Step-by-step explanation:
We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2
the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14
</span>
