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2 years ago

8

Which state of matter is this:Particles vibrate and change positions

2 answers:

babunello [35]2 years ago

8 0

Gas vibrate and move freely at high speeds. liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place.

xeze [42]2 years ago

5 0

Liquiddddddddddddddd

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Burka [1]

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2 years ago

How does salt dissolve in water?

iogann1982 [59]

Water<span> can </span>dissolve salt<span> because the positive part of</span>water<span> molecules attracts the negative chloride ions and the negative part of </span>water<span> molecules attracts the positive sodium ions</span>

7 0

2 years ago

What is the half-life of a first-order reaction if it takes 4.4 x 102 seconds for the concentration to decrease from 0.50 M to 0

elena55 [62]

Answer: The half-life of a first-order reaction is, $3.3\times 10^2s$

Explanation:

All the radioactive reactions follows first order kinetics.

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = ?

t = time taken = 440 s

$[A_o]$ = initial amount of the reactant = 0.50 M

[A] = left amount = 0.20 M

Putting values in above equation, we get:

$k=\frac{2.303}{440s}\log\frac{0.50}{0.20}$

$k=2.083\times 10^{-3}s^{-1}$

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

Putting values in this equation, we get:

$t_{1/2}=\frac{0.693}{2.083\times 10^{-3}s^{-1}}=332.69s=3.3\times 10^2s$

Therefore, the half-life of a first-order reaction is, $3.3\times 10^2s$

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2 years ago

Be + S electron transfermation

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Explanation:

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3 0

2 years ago

Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) O -7

11Alexandr11 [23.1K]

Explanation:

For an isothermal process equation will be as follows.

W = nRT ln $\frac{P_{1}}{P_{2}}$

It is given that mass is 10 kg/s or 10,000 g/s (as 1 kg = 1000 g). So, calculate number of moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{10000 g/s}{18 g/mol}$

= 555.55 mol/s

= 556 mol/s (approx)

As T = $50^{o}C$ or (50 + 273.15) K = 323.15 K. Hence, putting the given values into the above formula as follows.

W = nRT ln[/tex]\frac{P_{1}}{P_{2}}[/tex]

= $556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times ln\frac{1}{10}$

= $556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times -2.303$

= -3440193.809 J/s

Negative sign shows work is done by the pump. Since, 1 J = 0.001 kJ. Therefore, converting the calculated value into kJ as follows.

$3440193.809 J/s \times \frac{0.001 kJ}{1 J}$

= 3440.193 kJ/s

= 3451 kJ/s (approx)

Thus, we can conclude that the pump work is 3451 kJ/s.

6 0

3 years ago