Answer:
- Current market value of silver produced in the experiment = $0.2763
- Check Explanation for the appearance of leftover copper wire used in the experiment.
Explanation:
Price of Silver on today's market = $15.34 per troy ounce
Amount of Silver produced in the experiment = 0.56 g
31.1 g = 1 troy ounce
0.56 g = (0.56/31.1) = 0.01801 troy ounce
1 troy ounce = $15.34
0.01801 troy ounce = 0.01801 × $15.34 = $0.2763
The original reaction to extract the silver is one between Copper metal and the Silver Nitrate.
The Copper metal dissolves in the Silver Nitrate to give Copper Nitrate thereby displacing the Silver ion to become silver metal which we just valued above. But copper nitrate is a blue solution, So, it is a good estimate to say that the entire solution changed to that blue colour and the appearance of the leftover copper metal is colour blue. The silver metal forms as fractal-like crystals on this leftover copper.
Hope this Helps!!!
Answer : Option C) The Octet Rule
Explanation : Atoms have a tendency to complete their outer energy level. This is known as Octet Rule.
The octet rule is a chemical rule of thumb which reflects the observation, that atoms of main-group elements tends to combine in such a way that each atom gets eight electrons in its valence shell, which gives it the same electron configuration as that of a noble gas.
In short, the tendency of an atom to fill its valence shell and attain a stable state it acquires or donates the electron is called as octet rule.
Answer:
Yes
Explanation:
By definition, the equilibrium constanct, Kc, for the reaction A ⇒ 2B is
= [A]^1 / [B]^2
Substitute [A] = 4 and [B] = 2 in the equation,
[A]^1 / [B]^2
= 4^1 / 2^2
= 1
= Kc
So yes the reaction is at equilibrium.
Answer:
(a) the mass of the water is 3704 g
(b) the mass of the water is 199, 285.7 g
Explanation:
Given;
Quantity of heat, H= 8.37 x 10⁶ J
Part (a) mass of water (as sweat) need to evaporate to cool that person off
Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg
H = m x Lvap.
mass in gram ⇒ 3.704 kg x 1000g = 3704 g
Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J
specific heat capacity of water, C, 4200 J/kg.°C
H = mcΔθ
where;
Δθ is the change in temperature = 35 - 25 = 10°C
mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g
