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pishuonlain [190]
3 years ago
9

Based on this information which alternative energy source should the community consider investing in

Chemistry
1 answer:
vova2212 [387]3 years ago
7 0
Based on what info ?
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There are two different compounds of sulfur and fluorine.
olga nikolaevna [1]
What's your question......................
5 0
4 years ago
For which process would the pictured cell be used?
DaniilM [7]

Answer:

Coating a material with metal

(SInce the glasses will be coated with gold.)

3 0
2 years ago
Solid magnesium hydroxide decomposes into solid magnesium oxide and gaseous water . Write a balanced chemical equation for this
konstantin123 [22]
Equation: MgOH2 (s) --> MgO (s) + H2O (g)

And it's already balanced.

I had chemistry this semester too.
3 0
3 years ago
Read 2 more answers
A rectangular block of solid carbon (graphite) floats at the interface of two immiscible liquids.
Sergio039 [100]

Explanation:

Let us take the volume of block is x.

Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

                F_{net} = Buoyancy force(F_{b}) - weight force(w)

Also, buoyancy force (F_{b}) = (volume submerged in water × density of water) + (volume in oil × density of oil)

          (F_{b}) = (0.592 V \times \rho) + (1 - 0.592)V \times 1000 g          

                      = (0.592 V \times \rho + 408 V) g

As,   W = V × density of graphite × g

It is given that density of graphite is 2.16 g/cm^{3} or 2160 kg/m^{3}.

So, W = 2160 V g

F_{net} = (0.592 V \rho + 408 V) g - 2160 V g = 0

            0.592 \rho = 1752

     \rho = 2959.46 kg/m^{3} or 2.959 g/cm^{3} is the density of oil.

It is given that mass of flask is 124.8 g.

Mass of 35.3 cm^{3} oil = 35.3 \times 2.959 104.7 g

Hence, in second weighing total mass will be calculated as follows.

                       (124.8 + 104.7) g

                       = 229.27 g

Thus, we can conclude that in the second weighing mass is 229.27 g.

5 0
3 years ago
at standard pressure how do the boiling point and the freezing point of NaCl compare to the boiling point and freezing point of
Ede4ka [16]
Usually in this context you would be referring to the boiling and freezing point of a NaCl <em>solution</em> (saltwater) compared to pure H_{2}O. Sematics would be different for NaCl compound itself, you would say melting and boiling point for a solid substance- and the temperatures would be very, very radical (high). 
The boiling point of pure water is 100 degrees C (212 F), and the freezing/melting point is below 0 degrees C (32 F). For a salt water solution, the boiling point is raised and the melting point is lowered. This means that water will stay liquid for an increased range of temperature. Depending on the amount of NaCl solute in the water, the boiling and melting points may change a few degrees.
7 0
3 years ago
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