Answer: Physical change : tearing of paper, fixing of wtaer
Chemical change: rusting of iron , electrolysis of water, Rancidification
Explanation:
Physical change is a change in which there is no rearrangement of atoms and thus no new substance is formed. There is only change in physical state of the substance.
Example: tearing of paper, fixing of wtaer
Chemical change is a change in which there is rearrangement of atoms and thus new substance is formed. There may or may not be a change in physical state.
Example: rusting of iron , electrolysis of water, Rancidification
Acetylsalicylic acid (ASA) or commonly known as aspirin is used as pain reliever, treatment for fever and inflammation. The type of bond that aspirin have is covalent bond. Covalent bond is when atoms share their electrons. Aspirin is made up of carbon, hydrogen and oxygen with a formula of C9H8O4.
I need more info this is not enough but I think it’s 2 of electron and 7 nitrogen which is acetic mass
Using the ideal gas equation:
pV = nRT
n = pV / RT
1atm = 101325Pa, so p = 10132500Pa
1L = 0.001m^3, so V = 0.050m^3
R = 8.214 (ideal gas constant)
T = 273K
Hence moles of CO2 = (10132500 * 0.050) / (8.314 * 273) = 223.2101553
Reaction ratio between oxygen and CO2 is 1:2
Hence moles of O2 = 223... / 2 = 112 moles (3sf)
Explanation:
It is given that aluminium nitrate and calcium chloride are mixed together with sodium phosphate.
And, 
Let us assume that the solubility be "s". And, the reaction equation is as follows.
s = 
Also, 
s = 
This means that first, aluminium phosphate will precipitate.
Now, we will calculate the concentration of phosphate when calcium phosphate starts to precipitate out using the 
expression as follows.
![K_{sp} = [Ca^{2+}]^{3}[PO^{3-}_{4}]^{2}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5E%7B3%7D%5BPO%5E%7B3-%7D_%7B4%7D%5D%5E%7B2%7D)
![2.0 \times 10^{-29} = (0.016)^{3}[PO^{3-}_{4}]^{2}](https://tex.z-dn.net/?f=2.0%20%5Ctimes%2010%5E%7B-29%7D%20%3D%20%280.016%29%5E%7B3%7D%5BPO%5E%7B3-%7D_%7B4%7D%5D%5E%7B2%7D)
![2.0 \times 10^{-29} = 4.096 \times 10^{-6} \times [PO^{3-}_{4}]^{2}](https://tex.z-dn.net/?f=2.0%20%5Ctimes%2010%5E%7B-29%7D%20%3D%204.096%20%5Ctimes%2010%5E%7B-6%7D%20%5Ctimes%20%5BPO%5E%7B3-%7D_%7B4%7D%5D%5E%7B2%7D)
![[PO^{3-}_{4}]^{2}](https://tex.z-dn.net/?f=%5BPO%5E%7B3-%7D_%7B4%7D%5D%5E%7B2%7D)
= 
= 
M
Similarly, calculate the concentration of aluminium at this concentration of phosphate as follows.
![K_{sp} = [Al^{3+}][PO^{3-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAl%5E%7B3%2B%7D%5D%5BPO%5E%7B3-%7D_%7B4%7D%5D)
![9.84 \times 10^{-21} = [Al^{3+}] \times 2.21 \times 10^{-12}](https://tex.z-dn.net/?f=9.84%20%5Ctimes%2010%5E%7B-21%7D%20%3D%20%5BAl%5E%7B3%2B%7D%5D%20%5Ctimes%202.21%20%5Ctimes%2010%5E%7B-12%7D)
![[Al^{3+}] = 4.45 \times 10^{-9}](https://tex.z-dn.net/?f=%5BAl%5E%7B3%2B%7D%5D%20%3D%204.45%20%5Ctimes%2010%5E%7B-9%7D)
M
Thus, we can conclude that concentration of aluminium will be 
M when calcium begins to precipitate.
