Answer:
72.0 mL of steam is formed.
Explanation:
The reaction is :
You can treat coefficient of compounds as amount of volume used.
Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.
For 1 mL of ammonia (=1.25) mL of oxygen is used to form (=1) mL of nitric oxide gas and (=1.5) mL of steam.
OR
Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of become one like this
We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :
<em>1. </em><em>Assume ammonia to be completely exhausted</em>
For 50 mL of ammonia (= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.
2. <em>Assume oxygen to be completely exhausted</em>
For 60 mL of oxygen only (=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.
Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form (= 48) mL of nitic oxide gas and (= 72) mL of steam.
Therefore <em>72 mL of steam </em>is formed.
Answer:
The frequency
Step-by-step explanation:
The formula for the energy of an electromagnetic wave is
E = hf Thus,
E ∝ f and
f ∝ E
Answer:
<u>Optical purity = 76.9231 %</u>
<u>Specific rotation of mixture = - 97.6923 °</u>
Explanation:
The mass of the racemic mixture = 3 g
It means it contains R enantiomer = 1.5 g
S enantiomer = 1.5 g
Amount of Pure R = 10 g
Total R = 11.5 g
Total volume = 500 mL + 500 mL = 1000 mL = 1 L
[R] = 11.5 g/L
[S] = 1.5 g/L
Enantiomeric excess = = = 76.9231 %
<u>Optical purity = 76.9231 %</u>
Also,
Optical purity =
Optical rotation of pure enantiomer = −127 °
<u>Specific rotation of mixture = - 97.6923 °</u>
Answer:
2AlCl3 + Ca3N2 - 2AlN+ 3CaCl2