Question

Consult Interactive Solution 4.65 before beginning this problem. A toboggan slides down a hill and has a constant velocity. The angle of the hill is 6.00° with respect to the horizontal. What is the coefficient of kinetic friction between the surface of the hill and the toboggan

Answer 1

Answer:

$\mu_k=0.14$

Explanation:

It is given that,

The angle of the hill is 6.00° with respect to the horizontal. Let $\mu_k$ is the coefficient of kinetic friction between the surface of the hill and the toboggan.

A toboggan slides down a hill and has a constant velocity. On an inclined plane, force of friction will also act.

Force of friction, $f_k=mg\ sin\theta$...........(1)

Normal force, $N=mg\ cos\theta$............(2)    

From equation (1) and (2) :

$\mu_kmg\ cos\theta=mg\ sin\theta$

$\mu_k=tan\theta$

$\mu_k=tan(8)$                                      

$\mu_k=0.14$

So, the coefficient of kinetic friction between the surface of the hill and the toboggan is 0.14. Hence, this is the required solution.