The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
<h3>What current flows through the bulb as well as the power of the bulb?</h3>
From ohm's law; V = I × R
Where V is the voltage, I is the current and R is the resistance.
Also, Power is expressed as; P = V × I
Where V is voltage and I is current.
Given that;
- Resistance R = 10.0 ohms
- Voltage V = 12.0V
- Current I = ?
- Power P = ?
First, we determine the current flow through the bulb.
V = I × R
12.0V = I × 10.0 ohms
I = 12.0 ÷ 10.0
I = 1.2A
Next, we determine the power of the bulb.
P = V × I
P = 12.0V × 1.2A
P = 14.4 Watts
Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
Learn more about Ohm's law here: brainly.com/question/12948166
#SPJ1
Answer:
Explanation:
Given that,
First Capacitor is 10 µF
C_1 = 10 µF
Potential difference is
V_1 = 10 V.
The charge on the plate is
q_1 = C_1 × V_1 = 10 × 10^-6 × 10 = 100µC
q_1 = 100 µC
A second capacitor is 5 µF
C_2 = 5 µF
Potential difference is
V_2 = 5V.
Then, the charge on the capacitor 2 is.
q_2 = C_2 × V_2
q_2 = 5µF × 5 = 25 µC
Then, the average capacitance is
q = (q_1 + q_2) / 2
q = (25 + 100) / 2
q = 62.5µC
B. The two capacitor are connected together, then the equivalent capacitance is
Ceq = C_1 + C_2.
Ceq = 10 µF + 5 µF.
Ceq = 15 µF.
The average voltage is
V = (V_1 + V_2) / 2
V = (10 + 5)/2
V = 15 / 2 = 7.5V
Energy dissipated is
U = ½Ceq•V²
U = ½ × 15 × 10^-6 × 7.5²
U = 4.22 × 10^-4 J
U = 422 × 10^-6
U = 422 µJ
Answer:
The final speed at the gree light is 5.714 m/s
Explanation:
Given that,
Initial speed of the motorist (U) = 20m/s
Displacement of the traffic light (S) = 200m
time taken to slam the brake (t₁) = 1s
Now, the displacement of the motorist, till she slams the brake
S₁ = U × t₁
= 20 × 1
= 20m
The remaining distance would be
S₂ = S - S₁
S₂ = 200 - 20
S₂ = 180m
Now, the deceleration of the motorist
S₂ = Ut + 1/2at²
180 = (20 × 14) + 0.5a(14)²
a = - 1.02m/s²
The final speed would be
v = u + at
v = 20 + (- 1.02)(14)
v = 5.714 m/s
The final speed at the gree light is 5.714 m/s
Answer:
The temperature of the gas is 350.02 K.
Explanation:
The average speed is related to the temperature as follows:
(1)
Where:
: is the average speed = 1477 m/s
R: is the gas constant = 8.31 J/(K*mol)
T. is the temperature =?
M: is the molar mass
First, let's find the molar mass:
Where:
m: is the mass of the gas = 0.008 kg
n: is the number of moles = 2 mol
Hence, by solving equation (1) fot T we have:
Therefore, the temperature of the gas is 350.02 K.
I hope it helps you!
