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Harrizon [31]
4 years ago
6

A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C

a2 Ca2 per liter (mEq/L) for this solution
Chemistry
1 answer:
Romashka [77]4 years ago
3 0

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}

Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}

Equivalent weight is calculated by dividing the molecular weight by n factor.   {\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}

n= charge for charged species  , For Ca^{2+} , n =2

{\text{Equivalent weight}}=\frac{40}{2}=20g

\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents

Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L

Thus there will be 0.00002 meq per Liter of the solution.

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